No 5/8 is not greater then 2/3, 5/8 is just 1/24 smaller then 2/3.
4s+7a=861
s+a=168
This can be solved using either elimination or substitution. I am going to use substitution.
Solve s+a=168 for s
s=168-a
Replace 168-a for s in 4s+7a=861
4(168-a)+7a=861
672-4a+7a=861
Solve for a
672+3a=861
3a=189
a=63
Substitute 63 for a in s=168-a
s=168-63=105
So, s=105 student tickets and a=63 adult tickets
Answer:
58°
Step-by-step explanation:
If m AM=125°, then m∠AOM=125°.
If m∠MAF=75°, then m∠MOF=150° (because central angle MOF subtends on the same arc as inscribed angle MAF).
Thus,
m∠FOA=360°-150°-125°=85°.
If mEF=31°, then m∠EOF=31° (as central angle subtended on the arc EF).
Hence,
m∠EOA=m∠EOF+m∠FOA=31°+85°=116°.
Angle EOA is central angle subtended on arc EA, angle AME is inscribed angle subtended on arc AE, thus
m∠AME=1/2m∠EOA=58°.
The lines are perpendicular to each other because the graph of y = –6 is a horizontal line with a slope that is undefined, and the graph of x = 1/6 is a vertical line with a slope of 0.
The lines are perpendicular to each other because the graph of y = –6 is a vertical line with a slope that is undefined, and the graph of x =1/6 is a horizontal line with a slope of 0.
The lines are perpendicular to each other because the graph of y = –6 is a vertical line with a slope of 0, and the graph of x =1/6 is a horizontal line with a slope that is undefined.
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The lines are perpendicular to each other because the graph of y = –6 is a horizontal line with a slope of 0, and the graph of x =1/6 is a vertical line with a slope that is undefined.
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Brother one: x
Brother two: x + 15
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Make them add up to 55 in an equation.
x + (x + 15) = 55
Combine like terms.
2x + 15 = 55
Subtract 15 from both sides.
2x = 40
Divide both sides by 2.
x = 20
Plug 20 for x into brother two.
(20) + 15 = 35
Brother one has saved $20, brother two has saved $35.
