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shutvik [7]
3 years ago
7

Solve the inequality lxl <5.

Mathematics
1 answer:
Lorico [155]3 years ago
7 0

Answer:

can you check if you wrote this correctly

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Use elimination to solve the system of equations. Show your work 5×-3y=6,2×+5y=-10.
Fofino [41]

Answer:

5(5x-3y=6)

3(2x+5y=-10)

25x-15y=30

6x+15y=-30

31x= 0

x = 0

5(0)-3y=6

-3y=6

y= -2

(0,-2)

6 0
3 years ago
Read 2 more answers
Write as a unit rate: 36 gallons to 9 minutes *
Nataly_w [17]

Answer

36/9= 4

Step-by-step explanation:

This is a fraction equal to

36 gallons ÷ 9 minutes

We want a unit rate where

1 is in the denominator,

so we divide top and bottom by 9

36 gallons ÷ 9

9 minutes ÷ 9

=

4 gallons

1 minute

=

4 gallons

minute

= 4 gallons per minute

7 0
2 years ago
The graph below plots a function f(x):
Karolina [17]
By definition we have that the average rate of change of the function is given by:
 AVR =  \frac{f(x2) - f(x1)}{x2 - x1}&#10;
 Substituting values we have:
 AVR = \frac{100 - 50}{2 - 0}
 Rewriting we have:
 AVR = \frac{50}{2}
 AVR = 25
 Answer:
 If x represents time, the average rate of change of the function f(x) in the first two seconds is 25.
4 0
3 years ago
Triangle $ABC$ has a right angle at $B$. Legs $\overline{AB}$ and $\overline{CB}$ are extended past point $B$ to points $D$ and
Lisa [10]

Answer:

Given :

ABC is a right triangle in which ∠ABC = 90°,

Also, Legs AB and CB are extended past point B to points D and E,

Such that,

\angle EAC = \angle ACD = 90^{\circ}

To prove :

EB\times BD=AB\times BC

Proof :

In triangles AEC and EBA,

∠EAC= ∠ABE ( right angles )

∠CEA = ∠AEB ( common angles )

By AA similarity postulate,

\triangle AEC \sim \triangle EBA,

Similarly,

\triangle AEC \sim \triangle ABC

\implies\triangle EBA\sim \triangle ABC-----(1)

Now, In triangles ADC and CBD,

∠ACD = ∠CBD ( right angles )

∠ADC= ∠BDC ( common angles )

By AA similarity postulate,

\triangle ADC \sim \triangle CBD,

Similarly,

\triangle ADC \sim \triangle ABC

\implies \triangle CBD\sim \triangle ABC-----(2)

From equations (1) and (2),

\triangle EBA\sim \triangle CBD

The corresponding sides of similar triangles are in same proportion,

\frac{EB}{BC}=\frac{AB}{BD}

\implies EB\times BD=AB\times BC

Hence, proved....

5 0
3 years ago
Please help me out you guys
s344n2d4d5 [400]

Answer:

okok I willl hel0 you out

5 0
3 years ago
Read 2 more answers
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