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STatiana [176]
3 years ago
13

The diameter of a circle is 40 m. Find the area of the circle in terms of pi

Mathematics
1 answer:
VashaNatasha [74]3 years ago
3 0

Answer: 400π

Step-by-step explanation:

The formula for the area of a circle is πr²

First you have to calculate the radius by halving the diameter so radius is 20m.

Then you put in your calculator πx20²

This equals 400π (in terms of pi).

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Answer: 1.4 m/s

Explanation: the acceleration equation is a = change in velocity/change in time.

Plug the values in and you get 5.6/4

Divide and get 1.4 m/s
6 0
3 years ago
Isaac invested $77,000 in an account paying an interest rate of 4.6% compounded continuously. Assuming no deposits or withdrawal
zlopas [31]

Answer:

132,090.30

Step-by-step explanation:

r = R/100

r = 4.6%/100

r = 0.046 per year,

A = P(1 + r/n)nt

A = 77,000.00(1 + 0.046/1)(1)(12)

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3 0
2 years ago
Read 2 more answers
In a 2-card hand, what is the probability of holding only face cards?
SVEN [57.7K]

Answer:

12

Step-by-step explanation:

( J , Q, K 4 each)

so prob that for 2 cards, both cards are face

= C(12,2)/C(52,2) = 66/1326 = 11/221

4 0
3 years ago
PLEASE HELP!! This is due in less than 5 minutes or I fail!!!
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Answer:

A/ I think

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Find the coordinates of the missing endpoint if P is the midpoint of Line Segment NQ.
dimaraw [331]
  • Midpoint formula is (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) .
<h3>19.</h3>

So starting with this one, we will be solving for the coordinates of the unknown endpoint separately. Starting with the x-coordinate, since we know that the midpoint x-coordinate is 5 and the x-coordinate of N is 2, our equation is set up as such: \frac{x+2}{2}=5 From here we can solve for the x-coordinate of Q.

Firstly, multiply both sides by 2: x+2=10

Next, subtract both sides by 2 and your x-coordinate is x=8

With finding the y-coordinate, it's a similar process as with the x-coordinate except that we are using the y-coordinates of the midpoint and endpoint N.

\frac{y+0}{2}=2\\ y=4

<u>Putting it together, the missing endpoint is (8,4).</u>

<em>(The process is pretty much the same with the other problems, so I'll go through them real quickly.)</em>

<h3>20.</h3>

\frac{x+5}{2}=6\\ x+5=12\\ x=7

\frac{y+4}{2}=3\\ y+4=6\\ y=2

<u>The missing endpoint is (7,2).</u>

<h3>21.</h3>

\frac{x+3}{2}=-1\\ x+3=-2\\ x=-5

\frac{y+9}{2}=5\\ y+9=10\\y=1

<u>The missing endpoint is (-5,1).</u>

8 0
3 years ago
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