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bezimeni [28]
3 years ago
9

Which expression is equivalent to? Please help! Screenshots attached.

Mathematics
2 answers:
Softa [21]3 years ago
8 0

Answer:

\frac{\sqrt{5} }{x^{2} y}

Step-by-step explanation:

That's a complex expression, let's simplify it, step by step, off the start, we'll simplify the 55/11:

\sqrt{ \frac{55 x^{7} y^{6} }{11 x^{11} y^{8} } } = \sqrt{ \frac{5 x^{7} y^{6} }{x^{11} y^{8} } }

Then we'll simplify the x's and y's:

\sqrt{ \frac{5 x^{7} y^{6} }{x^{11} y^{8} } } = \sqrt{ \frac{5}{x^{4} y^{2} } }

Let's split the square root in two and solve the bottom part:

\sqrt{ \frac{5}{x^{4} y^{2} } } = \frac{\sqrt{5} }{\sqrt{x^{4} y^{2}} } = \frac{\sqrt{5} }{x^{2} y}

The solution is then:

\frac{\sqrt{5} }{x^{2} y}

sineoko [7]3 years ago
6 0
<h2>Answer:</h2>

The expression which is equivalent to the given expression is:

          \dfrac{\sqrt{5}}{x^2y}

<h2>Step-by-step explanation:</h2>

We are given a expression as:

     \sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}

Now we know that:

55=11\times 5

Hence, we get:

 \sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{11\times 5x^7y^6}{11x^{11}y^8}

which is written as:

\sqrt{\dfrac{5x^7y^6}{x^{11}y^8}}

Also, we know that if n>m

Then

\dfrac{a^m}{a^n}=\dfrac{1}{a^{n-m}}

Hence, we have the expression as:

=\sqrt{\dfrac{5}{x^{11-7}y^{8-6}}}\\\\\\=\sqrt{\dfrac{5}{x^4y^2}

This could be given as:

=\dfrac{\sqrt{5}}{\sqrt{x^4}\sqrt{y^2}}

Now, we know that:

\sqrt{x^4}=\sqrt{(x^2)^2}=x^2\\\\and\\\\\sqrt{y^2}=y

Hence, we get that:

\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt{5}}{x^2y}

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If AB=2(x+1) BC=3x+1 and AC=4(x+2) then find the value for x,AB,BC and AC
taurus [48]

Givens

AB + BC = AC

AB = 2(x + 1)

BC = 3x + 1

AC = 4(x + 2)

Substitute and Solve

AB + BC = AC

2(x + 1) + 3x + 1 = 4(x + 2)     Remove the brackets on the left

2x + 2 + 3x + 1 = 4(x + 2)      Collect the like terms on the left

5x + 3  = 4(x + 2)                  Remove the brackets on the right.

5x + 3 = 4x + 8                     Subtract 4x from both sides.

5x - 4x + 3 = 8            

x + 3 = 8                               Subtract 3 from both sides

x =8 - 3

x = 5

Answers

AB=2(5 + 1) = 2 * 6 = 12

BC = 3x + 1 = 3*5 + 1 = 15 + 1 = 16

AC = 4(5 + 2) = 4*7 = 28


7 0
4 years ago
In ΔIJK, the measure of ∠K=90°, KJ = 65, IK = 72, and JI = 97. What is the value of the cosine of ∠J to the nearest hundredth?
kow [346]

Answer:

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Step-by-step explanation:

Given

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The question is illustrated with the attached image.

From the image, we have:

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This gives:

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\cos(J) = 0.67010309278

\cos(J) = 0.67 --- approximated

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