What are the domain and Range of f(x)=Log(x+6)-4

Mathematics

1 answer:

Dominik [7]2 years ago

5 0

$f(x)=\log(x+6)-4\\\\\text{The domain:}\\x+6 \ \textgreater \ 0\to x \ \textgreater \ -6\to x\in(6;\ \infty)\\\\\text{the range of}\ y=\log x\ \text{is}\ \mathbb{R}\\\text{and the range of}\ y=\log(x+6)\ \text{is}\ \mathbb{R}\\\text{and the range of}\ f(x)=\log(x+6)-4\ \text{is}\ \mathbb{R}$

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3) 8x - 27 = 8(x-4) + 5<br> A) { All real numbers. }<br> B) (-7)<br> C) 7<br> D) {-10)

vfiekz [6]

The answer is A
8x-27=8x-32+5
Delete 8x
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2 years ago

A flash disk has the capacity of storing 1 megabyte of data. How many kilobytes of data can be stored in the same flash disk

Luden [163]

For this sort of problem, you need to be familiar with prefixes.

So:

megabyte = $1 *10^6$ bytes

kilobyte = $1*10^3$ bytes

and a regular byte would just be $1$

Now, you will need to do a conversion:

$1megabyte*\frac{1*10^6bytes}{1megabyte}*\frac{1*10^{-3}kilobyte}{1byte}$

I'm going to explain this just in case, but we convert megabytes to regular bytes in the first half by using the information I gave you above. (In one megabyte, there are $1*10^6$ bytes!)

In the second fraction thought, remember one kilobyte is $1*10^3$ bytes. However, you usually only see one of each thing on the bottom of fractions, so you need to add a negative sign to the 3. (technically you could just do $\frac{1kilobyte}{1*10^3bytes}$ , but I think it is more correct to do write it out how I did).