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Mathematics

1 answer:

crimeas [40]3 years ago

4 0

The correct answer is 104 fl oz = 13 c

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Part A: Find the GCF of 56 and 96. It is 8, already did this

enot [183]

Question: Part A: Find the GCF of 56 and 96. It is 8, already did this

Part B: Using the GCF you found in Part A, rewrite 56 + 96 as two factors. One factor is the GCF and the other is the sum of two numbers that do not have a common factor. Show your work.

Answer & explanation: Quick-Start Guide. When you enter an expression into the calculator, the calculator will simplify the expression by expanding multiplication and combining like terms. This website will help you out, I think! https://wpblog.wyzant.com lessons Expression Factoring Calculator – Wyzant Lessons

3 0

3 years ago

7 thousands 4 tens divided by 10

Bezzdna [24]

Answer:

704

Step-by-step explanation:

7000 + 40 (7 thousands + 4 Tens) Divide that by 10.

7040/10 = 704

6 0

3 years ago

Read 2 more answers

What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)

zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

Integrals
Definite Integrals
Integration Constant C

Arc Length Formula [Parametric]: $\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

Step 2: Find Arc Length

[Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]: $\displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.$
Substitute in variables [Arc Length Formula - Parametric]: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx$
[Integrand] Simplify: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx$
[Integral] Evaluate: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}$