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cestrela7 [59]
3 years ago
9

bryan rides the bus to and from work on the days he works at the library in one month he rode the bus 24 times solve the equatio

n 2x=24 to find the number of days bryan worked at the library
Mathematics
2 answers:
posledela3 years ago
6 0
He worked there for 12 days that month

Margarita [4]3 years ago
4 0
So the answer is the 48
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Find the equation of the circle whose center and radius are given. Center:(-2,-5) Radius=1
maxonik [38]

Answer:

( x+2)^2 + (y+5)^2 = 1

Step-by-step explanation:

The equation of a circle can be written in the form

( x-h)^2 + (y-k)^2 = r^2

where ( h,k) is the center and r is the radius

( x- -2)^2 + (y- -5)^2 = 1^2

( x+2)^2 + (y+5)^2 = 1

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The volume of the square pyramid is 600cm^3
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Find the vertex and the axis of symmetry of the graph of f(x)=3(x+1)^2
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General form of vertex of a parabola is

y  = a(x - b)^2 + c     where vertex  = (b , c)


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I would like to know: how many 1/3 are in 1 2/3
inysia [295]

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There are 2

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Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. Illustra
Rainbow [258]

Answer:

x = t

y = 1 - t

z = 2t

Step-by-step explanation:

Given

x=t

y=e^{-t}

z=2t-t^2

(0, 1, 0)

The vector equation is given as:

r(t) = (x,y,z)

Substitute values for x, y and z

r(t) = (t,\ e^{-t},\ 2t - t^2)

Differentiate:

r'(t) = (1,\ -e^{-t},\ 2 - 2t)

The parametric value that corresponds to (0, 1, 0) is:

t = 0

Substitute 0 for t in r'(t)

r'(t) = (1,\ -e^{-t},\ 2 - 2t)

r'(0) = (1,\ -e^{-0},\ 2 - 2*0)

r'(0) = (1,\ -1,\ 2 - 0)

r'(0) = (1,\ -1,\ 2)

The tangent line passes through (0, 1, 0) and the tangent line is parallel to r'(0)

It should be noted that:

The equation of a line through position vector a and parallel to vector v is given as:

r(t) = a + tv

Such that:

a = (0,1,0) and v = r'(0) = (1,-1,2)

The equation becomes:

r(t) = (0,1,0) + t(1,-1,2)

r(t) = (0,1,0) + (t,-t,2t)

r(t) = (0+t,1-t,0+2t)

r(t) = (t,1-t,2t)

By comparison:

r(t) = (x,y,z) and r(t) = (t,1-t,2t)

The parametric equations for the tangent line are:

x = t

y = 1 - t

z = 2t

7 0
3 years ago
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