Can someone help me with question 2

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

7 0

You just have to add I think

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Find the values for x and y.

vivado [14]

Both sides need to equal 180 (The side with the 90 degrees measurement and the side with equations). So first subtract 180 from 90
$180 - 90$
to get the measurement of 5x and you get 90 but we aren't done yet since we need to find x so now we need to divide 5 by 90
$90 \div 5 = 18$
and we get 18 which is X.
$x = 18$
Now we need to find the measurement of Y. Now both angles on that side together equals 180 so we need this equation.
$5(y + 11) + 4y - 10 = 180$
First, distribute 5(y + 11)
$5 \times y \\ 5 \times 11$
Then you get this equation :
$5y + 55 + 4y - 10 = 180$
Now, add the two equations together
$5y + 55 + 4y - 10$
and you get this equation

$9y + 45 = 180$
Now subtract 45 from both sides
$9y + 45 - 45 = 180 - 45$
and divide by 9 on both sides
$9y \div 9 = 135 \div 9$
and you get your answer
$y = 15$

So
$x = 18$
and
$y = 15$

8 0

2 years ago

A ball rolls down an inclined plane such that the distance (in centimeters) that it rolls in t seconds is given by s(t) = 2t^3 +

IRISSAK [1]

The ball's velocity will be represented by the derivative of its distance function:

$s'(t)=6t^2+6t$

Now find the times $t$ for which this is equal to 30, i.e. solve

$6t^2+6t=30\implies t^2+t-5=0$

This has two solutions, $t=-\dfrac{1\pm\sqrt{21}}2$ , but only one is positive and falls in the interval $[0,3]$ . So the velocity reaches 30 cm/s when $t=-\dfrac{1-\sqrt{21}}2\approx1.79$ .