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Dima020 [189]
3 years ago
15

Can someone help me with question 2

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
7 0
You just have to add I think
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Help solve this plsss fast!!!
exis [7]

Answer:

2x + x + 5 = 6x - 3x + 5

3x + 5 = 3x + 5

Here Both the side of equation are same ..

So, it have infinite solution....

8 0
3 years ago
How would you describe the solution to this system of equations?
Amanda [17]

Answer:

reffrents a number

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x
qaws [65]

1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is (2x+10)^\circ, so the measure of arc DF is

m\widehat{DF}=360^\circ-180^\circ-(2x+10)^\circ=(170-2x)^\circ

The inscribed angle theorem tells us that the central angle subtended by arc DF, \angle DOF, has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

m\angle DOF=2m\angle OEF=64^\circ

so the measure of arc DF is also 64 degrees. So we have

170-2x=64\implies106=2x\implies\boxed{x=53}

###

2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

m\angle EFD+m\angle EDF+m\angle DEF=180^\circ\implies\boxed{m\angle EFD=76^\circ}

Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have

m\angle EFO+m\angle FEO+m\angle EOF=180^\circ\implies\boxed{m\angle EFO=62^\circ}

7 0
3 years ago
8 divided by 6.403 round to the nearest tenths
lions [1.4K]
I believe the answer is 1.2
6 0
3 years ago
Read 2 more answers
Brainliest for correct answer
Finger [1]
D hope this helps xx
3 0
3 years ago
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