I am looking on the answers, and there is only one case, when a or b or c or d pass: 3|x-3| + 2 = 14. So I assume, that before two is plus. Then:
3|x-3|+2=14 |minus 2
3|x-3|=12 |divide 3
|x-3|=4
From absolute value definition you've got two ways:
x-3=4 or x-3=-4
x=7 or x=-1
And answer d) passes
Answer:

Step-by-step explanation:
Slope intercept form is: 
<h2>
Find the Slope:</h2>
Choose 2 points on the graph:
(0,1) (2,0)
Find the slope of the two points:


<h2>Find the Y-Intercept</h2>
The y-intercept, or the point that the line crosses on the y axis, is (0,1).


It should be 78.54.
Double check that.
Formula: V=πr2h/3
r2 is R squared
So domain is the number you can use
range is the output your get from inputting the domain given
so from 2≤x≤5
since it is linear, we can be sure that we only need to test the endpoints of the domain to find the endpoints of the range
sub 2 for x
y=2(2)+1
y=4+1
y=5
sub 5 for x
y=2(5)+1
y=10+1
y=11
so range is from 5 to 11
in interval notation: [5,11]
in other notation 5≤y≤11
or
R={y|5≤y≤11}