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r-ruslan [8.4K]
2 years ago
15

Which equation has a maximum at y = 5 for 0 < x < 27?

Mathematics
1 answer:
Vinvika [58]2 years ago
6 0

Answer:

To determine which equation has a maximum at y =5, you will need to compare their graphs looking only at the x-values between 0 and 27.

Step-by-step explanation:

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katrin2010 [14]

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A

Step-by-step explanation:

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2 years ago
Which graph does not represent a function
Marysya12 [62]

Answer:

Graph D

Step-by-step explanation:

it does not pass the linear test to qualify as a function

3 0
3 years ago
Read 2 more answers
Find the dot product of the position vectors whose terminal points are (14, 9) and (3, 6).
erma4kov [3.2K]

Answer:

Step-by-step explanation:

The formula for the dot product of vectors is

u·v = |u||v|cosθ

where |u| and |v| are the magnitudes (lengths) of the vectors. The formula for that is the same as Pythagorean's Theorem.

|u|=\sqrt{14^2+9^2} which is \sqrt{277}

|v|=\sqrt{3^2+6^2} which is \sqrt{45}

I am assuming by looking at the above that you can determine where the numbers under the square root signs came from. It's pretty apparent.

We also need the angle, which of course has its own formula.

cos\theta=\frac{uv}{|u||v|} where uv has ITS own formula:

uv = (14 * 3) + (9 * 6) which is taking the numbers in the i positions in the first set of parenthesis and adding their product to the product of the numbers in the j positions.

uv = 96.

To get the denominator, multiply the lengths of the vectors together. Then take the inverse cosine of the whole mess:

cos^{-1}\theta=\frac{96}{111.64676} which returns an angle measure of 30.7. Plugging that all into the dot product formula:

u*v=\sqrt{277}*\sqrt{45}cos(30.7) gives you a dot product of 96

6 0
2 years ago
Can u tell me what the answer is plz
yuradex [85]

Answer:

D, B, C, A

Step-by-step explanation:

Solve the equations by combining like terms, isolating the variable, and dividing the equation by the coefficient of the variable.

Doing this, the first equation should be 2, the second equation should be -2, the third equation should be -1, and the last equation should be -6.

Then, we can order them.

8 0
3 years ago
Factor completely x2 + 16.<br><br> (x + 4)(x + 4)<br> (x + 4)(x − 4)<br> Prime<br> (x − 4)(x − 4)
Sindrei [870]
It's prime because the constant term is positive and there is no middle term. If it were x^2 - 16, we could use (x+4)(x-4), but because 16 is positive, it cannot be factored
4 0
3 years ago
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