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3 years ago

Numbers between 55 and 101 that is a multiple of 4 6 and 8

Mathematics

1 answer:

DENIUS [597]3 years ago

8 0

96
72
As a result, these two numbers are multiple of 4,6 and 8. Hope it help!

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F(x)=x+4and g(x)=x^3,what is (g f)(-3)

wel

If it is g(x) composed of f(x): 1 If it is g(x) times f(x): -27
(g•f)(-3) is multiplication, (gof)(-3) is composition.

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3 years ago

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The ratio of two numbers is 2/3. The sum of the numbers is 105. What are the two numbers?

Pepsi [2]

A) x/y = 2/3
B) x + y = 105
Solving Equation A for y
A) y = 1.5x
Substituting A into B
B) x + 1.5x = 105
2.5x = 105
x = 42
y = 63

8 0

3 years ago

Find the place value of 8 in 2456.1387. Tenths Hundredths Thousandths Thousands

rjkz [21]

Answer: Third Choice. Thousandths

Step-by-step explanation:

Concept:

Here, we need to know the order and name of each place value.

Please refer to the attachment below for the specified names.

Solve:

STEP ONE: Orde and name each place

2 ⇒ One Thousands

4 ⇒ Hundreds

5 ⇒ Tens

6 ⇒ Ones

1 ⇒ Tenths

3 ⇒ Hundredths

8 ⇒ One Thousandths

7 ⇒ Ten Thousandths

STEP TWO: Find the number [8] in the number

As we can see from the list above, 8 is at the right of the decimal point, thus, the place value is Thousandths.

Hope this helps!! :)

Please let me know if you have any questions

5 0

3 years ago

Find x and y helppppp !!

Anni [7]

3x + 6 = 48 (alternate angles are equal)

- 6

3x. = 42

÷3

x = 14 degrees

180-48 - 2y + 5y-9 =180

123 + 3y = 180

-123

3y = 57

÷3

y = 19 degrees

Explanation:

To find the last angle on the top straight line, do:

180 - (the 2 given angles).

So, 180 - (3x + 16, which is 48 due to alternate angles being equal). Then, minus the 2y.

(180 - 48 - 2y) & simplify => 132 - 2y

This gives you the equation for the missing angle on our top straight line.

Thus, co-interior angles add to 180. So, we add the new equation (132 - 2y) to 5y - 9.

Simplify

=> 123 + 3y (because - 2+5 =3)

and put it equal to 180. Solve for y

Hope this helps!

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2 years ago

An engineer is designing a storage compartment in a spacecraft .The compartment must be 2 meters longer than it is wide, and its

serg [7]

Answer:

Let x be the width of the compartment,

Then according to the question,

The length of the compartment = x + 2

And the depth of the compartment = x -1

Thus, the volume of the compartment, $V = (x+2)x(x-1) = x^3 + x^2 - 2x$

But, the volume of the compartment must be 8 cubic meters.

⇒ $x^3 + x^2 - 2x = 8$

⇒ $x^3 + x^2 - 2x - 8=0$

⇒ $(x-2)(x^2+3x+4)=0$

If $x-2=0\implies x = 2$ and if $x^2+3x+4=0\implies x = \text{complex number}$

But, width can not be the complex number.

Therefore, width of the compartment = 2 meter.

Length of the compartment = 2 + 2 = 4 meter.

And, Depth of the compartment = 2 - 1 = 1 meter.

Since, the function that shows the volume of the compartment is,

$V(x) = x^3 + x^2 - 2x$

When we lot the graph of that function we found,

V(x) is maximum for infinite.

But width can not infinite,

Therefore, the maximum value of V(x) will be 8.

8 0

4 years ago

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