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charle [14.2K]
3 years ago
14

Factor the expression. 6x + 6

Mathematics
2 answers:
pychu [463]3 years ago
6 0
6(x+1) is the answer
Aliun [14]3 years ago
3 0
6x+6
=6(x+1)
Answer is
6(x+1) have a nice day
< 3
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For her birthday, Clara wanted a balloon bouquet. If there are 4 colors to choose from and her bouquet will only have 4 balloons
AnnZ [28]

Answer:

35

Step-by-step explanation:

CR(n,r)=(n+r−1)!/r!(n−1)!

CR(n,r)=CR(4,4)

=(4+4−1)!/4!(4−1)!

= 35

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1. Michael obtained a 30-year, $90,000 mortgage with an interest rate of 8 percent, what is the interest For
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2 years ago
Pooky eats three cans of cat food each day. How long will 27 cans of food last?
djverab [1.8K]

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3 0
3 years ago
Read 2 more answers
Follow the directions to solve the system of equations by elimination. 8x + 7y = 39 4x – 14y = –68 Multiply the first equation t
Helga [31]

Answer:

x=½

y=5

Step-by-step explanation:

(8x+7y=39)2

16x+14y=78

<u>4</u><u>x</u><u>-</u><u>1</u><u>4</u><u>y</u><u>=</u><u>-</u><u>6</u><u>8</u> add the two equations

20x=10.

divide both sides by 20

x=½

8x+7y=39

4+7y=39

7y=39-4

7y=35

y=5

7 0
3 years ago
Read 2 more answers
Miki prepared two gallons of a beverage that contains tea and lemonade in the ratio tea:lemonade=3:1. If Miki then added one-hal
Advocard [28]

Ratio of tea to lemonade in the new mixture is 3 : 2

<h3><u>Solution:</u></h3>

Given that volume of a beverage prepared by Miki containing tea and lemonade = 2 gallons

Ratio of tea and lemonade in beverage prepared by Miki = 3:1  

Then Miki added one half of gallon of lemonade to the mixture.  

Need to determine ratio of tea and lemonade in the new mixture.

Lets first calculate volume of tea and volume of lemonade in old mixture that is the one before adding one half of gallon of lemonade.

Given ratio of tea and lemonade in old mixture = 3: 1 , means our of every four parts of mixture, 3 parts are of tea and 1 part is of lemonade.

=>\text { In old mixture, } \frac{3}{4} \text { is tea and } \frac{1}{4} \text { is lemonade. }

\text { Volume of tea in old mixture }=\frac{3}{4} \times \text { volume of old mixture }=\frac{3}{4} \times 2 \text { gallons }=1.5 \text { gallons }

\text { Volume of lemonade in old mixture }=\frac{1}{4} \times \text { volume of old mixture }=\frac{1}{4} \times 2 \text { gallons }=0.5 \text { gallons }

Given that one-half gallon of lemonade is added to old mixture to form new mixture.

So Volume of lemonade in new mixture = Volume of lemonade in old mixture + one half gallon = 0.5 + 0.5 = 1 gallon

As there is no change in volume of tea , so Volume of Tea in new mixture = Volume of tea in old mixture = 1.5 gallons

Ratio of tea : lemonade in new mixture = 1.5 : 1 = 3 : 2  

Hence ratio of tea to lemonade in the new mixture is 3 : 2.

7 0
3 years ago
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