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Zolol [24]
3 years ago
12

Help please

Mathematics
1 answer:
bonufazy [111]3 years ago
8 0

Answer:

Common difference = 5.

Step-by-step explanation:

General term of an arithmetic sequence is a1 + (n - 1)d where a1 = first term and d = common difference.

So here the first term is  8 + (1-1)d = 8 and the 10th term = 8 + (10-1)d = 53

giving 8 + 9d = 53

9d = 45

d = 5.

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Does 1.5cm, 3cm, 1.5cm form a trangle.
Vesnalui [34]

Answer:

yes because at least 2 measurements are equal

Step-by-step explanation:

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3 years ago
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Write an equation of the line, in point-slope form, that passes through the two given points.
Marat540 [252]

Answer:

(y-8) = -1/2(x+17)

Step-by-step explanation:

slope = (-2 - 8) / (3 - (-17)) = -10 / 20 = -1/2

5 0
2 years ago
Help ASAP I’ll mark you as brainlister PLEASE!!’
Alex17521 [72]

Answer:

A = 76.8 yd²

Step-by-step explanation:

The area (A) of a regular polygon is calculated as

A = \frac{1}{2} pa ( p is the perimeter and a the apothem )

Here p = 8 × 4 = 32 yd and a = 4.8 yd , then

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8 0
3 years ago
5.2 compared to 0.52
Black_prince [1.1K]

Answer:

10 times


Step-by-step explanation:


8 0
3 years ago
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The number of hours that a nine month old baby sleeps at night are normally distributed with a population standard deviation of
finlep [7]

Answer:

The margin of error for a confidence interval for the population mean with a 90% confidence level is 0.53 hours.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this quesstion:

\sigma = 1.5, n = 22

So

M = 1.645*\frac{1.5}{\sqrt{22}} = 0.53

The margin of error for a confidence interval for the population mean with a 90% confidence level is 0.53 hours.

4 0
3 years ago
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