3 years ago

Find a quadratic equation whose solution is -5 (only solution)

Mathematics

1 answer:

alukav5142 [94]3 years ago

5 0

X2-6x+5 is the quadratic eqution

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Given that f(x)= x2+3 and g(x)= x+4/3 solve for (f(g(x)) when x =2

Savatey [412]

$\bf \begin{cases}
f(x)=x^2+3\\\\
g(x)=x+\cfrac{4}{3}
\end{cases}
\\\\\\
\boxed{x=2}\qquad g(2)=(2)+\cfrac{4}{3}\implies \boxed{g(2)=\cfrac{10}{3}}
\\\\\\
f(~~g(x)~~)=[g(x)]^2+3\implies f(~~g(2)~~)=[g(2)]^2+3
\\\\\\
f(~~g(2)~~)=\left[ \boxed{\frac{10}{3}} \right]^2+3\implies f(~~g(2)~~)=\cfrac{10^2}{3^2}+3
\\\\\\
f(~~g(2)~~)=\cfrac{100}{9}+3\implies f(~~g(2)~~)=\cfrac{100+27}{9}
\\\\\\
f(~~g(2)~~)=\cfrac{127}{9}$

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3 years ago

Simplify ^3_/125x^21y^33

Grace [21]

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