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andrezito [222]
3 years ago
8

On Quiz

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
8 0

Answer:

C. g(x) = -2[x - 5)2 + 9

Step-by-step explanation:

Equation in vertex form

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4a+6b=10<br> 2a-4b=12<br><br> what does 12a =?
Usimov [2.4K]
If you have at least as many equations as your have unknown variables, the 'system' is solvable (unless the equations are copies of eachother).

In this case, isolate one letter and plug it in the other. I'm going for the 2a in the bottom one (it doesn't matter)

2a - 4b = 12 => (divide by two and move the b's to the other side)

a = 6 + 2b. (plug this one into the top equation)

4(6+2b) + 6b = 10 => 24+8b+6b = 10 => 24 + 14b = 10 => 14b = -14 => b=-1

a = 6 + -2 = 4.

So a=4 and b=-1. 


4 0
3 years ago
Evaluate 3-5 using a number line.​
Alekssandra [29.7K]

Step-by-step explanation:

= 3 - 5

= -2

line in the picture

4 0
2 years ago
X^2-3×=2 use quadratic equation ​
abruzzese [7]

Answer:

(-3+√17 )/2. or( -3-√17)/2

hope you got it

4 0
3 years ago
Express 1.21212121.... as a fraction
Elodia [21]
That would be 1 21/99  or  120/99 as an improper fraction.
7 0
3 years ago
Read 2 more answers
Show that sinxtanx=1-cos^2x/cosx
yawa3891 [41]
LHS: = \sin x \tan x =  \frac{\sin x \sin x }{\cos x} =  \frac{\sin^2 x}{\cos x} (using \tan x =  \frac{\sin x}{\cos x})

We know \sin^2x + \cos^2x = 1 \Rightarrow \sin^2x=1-\cos^2x so we can replace the sin²x in the LHS expression as follows

\frac{\sin^2x}{\cos x} =  \frac{1-\cos^2x}{\cos x} which is the RHS.
7 0
2 years ago
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