Answer:
Randy has eight $5 bills and nine $1 bills
Step-by-step explanation:
Randy needs $50.00
And we know that he his only $1.00 short, so he has $49.00
let's define:
x = number of $1 bills that he has
y = number of $5 bills that he has.
then:
x*$1 + y*$5 = $49
We know that he has one more $1 bills than $5 bills.
we can write this as
x = y + 1
So we have a system of two equations and two variables:
x*$1 + y*$5 = $49
x = y + 1
First we can see that the variable "x" is isolated in the second equation, now we can replace that in the other equation:
x*$1 + y*$5 = $49
(y + 1)*$1 + y*$5 = $49
now we can solve this for y.
y*$1 + $1 + y*$5 = $49
y*($1 + $5) = $49 - $1 = $48
y*$6 = $48
y = $48/$6 = 8
He has 8 $5 bills
and we know that:
x = y + 1
x = 8 + 1 = 9
he has 9 $1 bills.
False...it does not include 3....it includes only numbers less then 3.
For it to include 3, u would need an equal sign in there..
Y < = 3...(thats less then or equal)...this would include 3
Answer: it’s A or the 1st option
Step-by-step explanation:
Answer:
35 People
Step-by-step explanation:
From the given information
- $125 was charged for the rental of the hall
- Each Meal costs $12
- Total Bill = $545
Let the number of people attending the banquet=x
Therefore:
Cost of Hall Rental + Total Meal Cost = Total Bill
125+12x=545
12x=545-125
12x=420
x=420/12=35
Since x=35, we conclude that 35 People attended the banquet.
Answer:
1000
Step-by-step explanation:
1/2 (b x l x h)
1/2 (40 x 50)
1/2 (2000)
1000