<span><u>The answer is A. 72.25 percent.</u>
The Hardy-Weinberg principle can be used:</span>
<em>p² + 2pq + q² = 1</em> and <em>p + q = 1</em>
where <em>p</em> and <em>q</em> are the frequencies of
the alleles, and <em>p²</em>, <em>q²</em> and <em>2pq </em>are the
frequencies of the genotypes.
<span>The <em>r</em> allele (<em>q</em>) is found in 15% of the population:
q = 15% = 15/100
Thus, q = </span><span>0.15
To calculate the <em>R</em> allele frequency (<em>p</em>), the formula p + q = 1 is
used:
If p + q = 1, then p = 1 - q
p = 1 - 0.15
Thus, </span><span>p = 0.85
Knowing the frequency of the <em>R</em> allele (<em>p</em>), it is easy to determine the
frequency of the RR genotype (p²):
p² = 0.85² = 0.7225
Expressed in percentage, p² = 72.25%.</span>
They originate near the Equator!
Answer:
The probability of the parents having yellow-bellied off-spring is 100% because all the genotypes have a dominant Y.
It is possible for two yellow-bellied numbats to have a green bellied child if they are both hybrid Yy. The probability of the parents to have a green-bellied child is 25%
When h forms a bond with h2o to form hydronium ion, h3o , this bond is called a coordinate covalent bond.
