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3 years ago

Can you please help me with this I been stuck for a long time

Mathematics

1 answer:

yarga [219]3 years ago

3 0

Answer:

Step-by-step explanation:

2.671 = (2.67 × 100)(1 × 100) = 267100. As the numerator is greater than the denominator, we have an IMPROPER fraction, so we can also express it as a MIXED NUMBER, thus 267100 is also equal to 267100 when expressed as a mixed number.

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A boat traveled in a river upstream for a distance of 30 miles at a constant rate, r, in miles per hour, and then made the retur

ICE Princess25 [194]

Answer:

Step-by-step explanation:

r = boat's rate

c = current's rate

1. A boat traveled in a river upstream for a distance of 30 miles. Travelling upstream, the current obstructs the movement, so the actual boat's rate is r - c mph.

If the boat took 4 hours to travel upstream, then

$\dfrac{30}{r-c}=4\\ \\4(r-c)=30\\ \\4r-4c=30$

2. A boat traveled in a river downstream for a distance of 30 miles. Travelling downstream, the current helps the movement, so the actual boat's rate is r + c mph.

If the boat took 3 hours to travel downstream, then

$\dfrac{30}{r+c}=3\\ \\30=3(r+c)\\ \\3r+3c=30$

So, we get the system

4r-4c=30

3r+3c=30

8 0

4 years ago

Please help me with both problems thank you so much!!

motikmotik

The one on the left is -5/6
The one on the right is 1/21

6 0

3 years ago

Read 2 more answers

Which expression is equivalent to \frac{10q^5w^7}{2w^3}.\ \frac{4\left(q6\right)^2}{w^{-5}} for all values of q and w where the

mestny [16]

Answer:

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9$

Step-by-step explanation:

Given

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Required

Determine the equivalent expression

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Simplify the first fraction

$\frac{5q^5w^7}{w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Apply law of indices on the first fraction;

$5q^5w^{7-3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

$5q^5w^4.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

$\ \frac{5q^5w^4*4\left(q^6\right)^2}{w^{-5}}$

Apply law of indices:

$5q^5w^4*4\left(q^6\right)^2 * w^{5}$

Evaluate the bracket

$5q^5w^4*4 * q^{12} * w^{5}$

Collect Like Terms

$5*4q^5* q^{12}*w^4 * w^{5}$

$20q^5* q^{12}*w^4 * w^{5}$

$20q^{5+12}*w^{4+5}$

$20q^{17}w^9$

Hence:

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9$

7 0

3 years ago

Katarina wrote the standard form of a linear equation as 4x – 2/3 y = 8. Sofiya told her that the equation was not yet in standa

-BARSIC- [3]

The standard form of a linear equation in general is given by:

$ax+by=c$

Now we are given the equation :

$4x-\frac{2}{3}y=8$

In order to convert this into standard equation, we have to eliminate the 3 in the second term on the left side of equation.

Here 3 is in division ,so we have to perform opposite operation of division that is multiplication.

So multiplying both sides by 3 , we have

$12x-2y=24$

So that means option A.Multiply both sides of the equation by 3. The standard form of the equation is 12x – 2y = 24. is the correct advice given by Sofiya.

8 0

3 years ago

Read 2 more answers

W + 15 = 29 <br> w=___ ?? HELP

kykrilka [37]

Answer:

w=14

Step-by-step explanation:

29-15=14

7 0

3 years ago

Read 2 more answers