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Alexus [3.1K]
3 years ago
11

Can you please help me with this I been stuck for a long time

Mathematics
1 answer:
yarga [219]3 years ago
3 0

Answer:

Step-by-step explanation:

2.671 = (2.67 × 100)(1 × 100) = 267100. As the numerator is greater than the denominator, we have an IMPROPER fraction, so we can also express it as a MIXED NUMBER, thus 267100 is also equal to 267100 when expressed as a mixed number.

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A boat traveled in a river upstream for a distance of 30 miles at a constant rate, r, in miles per hour, and then made the retur
ICE Princess25 [194]

Answer:

D

Step-by-step explanation:

r = boat's rate

c = current's rate

1. A boat traveled in a river upstream for a distance of 30 miles. Travelling upstream, the current obstructs the movement, so the actual boat's rate is r - c mph.

If the boat took 4 hours to travel upstream, then

\dfrac{30}{r-c}=4\\ \\4(r-c)=30\\ \\4r-4c=30

2. A boat traveled in a river downstream for a distance of 30 miles. Travelling downstream, the current helps the movement, so the actual boat's rate is r + c mph.

If the boat took 3 hours to travel downstream, then

\dfrac{30}{r+c}=3\\ \\30=3(r+c)\\ \\3r+3c=30

So, we get the system

4r-4c=30

3r+3c=30

8 0
4 years ago
Please help me with both problems thank you so much!!
motikmotik
The one on the left is -5/6
The one on the right is 1/21
6 0
3 years ago
Read 2 more answers
Which expression is equivalent to \frac{10q^5w^7}{2w^3}.\ \frac{4\left(q6\right)^2}{w^{-5}} for all values of q and w where the
mestny [16]

Answer:

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9

Step-by-step explanation:

Given

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Required

Determine the equivalent expression

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Simplify the first fraction

\frac{5q^5w^7}{w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Apply law of indices on the first fraction;

5q^5w^{7-3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

5q^5w^4.\ \frac{4\left(q^6\right)^2}{w^{-5}}

\ \frac{5q^5w^4*4\left(q^6\right)^2}{w^{-5}}

Apply law of indices:

5q^5w^4*4\left(q^6\right)^2 * w^{5}

Evaluate the bracket

5q^5w^4*4 * q^{12} * w^{5}

Collect Like Terms

5*4q^5* q^{12}*w^4  * w^{5}

20q^5* q^{12}*w^4  * w^{5}

20q^{5+12}*w^{4+5}

20q^{17}w^9

Hence:

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9

7 0
3 years ago
Katarina wrote the standard form of a linear equation as 4x – 2/3 y = 8. Sofiya told her that the equation was not yet in standa
-BARSIC- [3]

The standard form of a linear equation in general is given by:

ax+by=c

Now we are given the equation :

4x-\frac{2}{3}y=8

In order to convert this into standard equation, we have to eliminate the 3 in the second term on the left side of equation.

Here 3 is in division ,so we have to perform opposite operation of division that is multiplication.

So multiplying both sides by 3 , we have

12x-2y=24

So that means option A.Multiply both sides of the equation by 3. The standard form of the equation is 12x – 2y = 24. is the correct advice given by Sofiya.


8 0
3 years ago
Read 2 more answers
W + 15 = 29 <br> w=___ ?? HELP
kykrilka [37]

Answer:

w=14

Step-by-step explanation:

29-15=14

7 0
3 years ago
Read 2 more answers
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