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Yanka [14]
3 years ago
8

Solve the given inequality and graph the solution on a number line. -x/2 + 3/2 < 5/2

Mathematics
1 answer:
Ket [755]3 years ago
7 0

Answer:

x > −2

Step-by-step explanation:

You need to isolate the variable. You can do this by first subtracting 3/2 from both sides of the inequality sign.

You will get -x/2 < 2/2.

Next, since x is being divided by -2, you will multiply it by -2 to undo it. Do this to both sides.

Note that when multiplying or dividing by a negative you will flip the inequality sign. '<' becomes '>' and '>' becomes '<'.

You will get x > -2.

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Write an expression for "the difference of 10 and x."<br> Help will give branily
Paul [167]

Answer:

10-x

Step-by-step explanation:

The difference of 10 and x is subtracting x from 10

7 0
3 years ago
Give an example of a function with both a removable and a non-removable discontinuity.
LekaFEV [45]

Answer:

(x+5) (x=3)

(X+5) (x+1)

Step-by-step explanation:

A removeable discontinuity is always found in the denominator of a rational function and is one that can be reduced away with an identical term in the numerator. It is still, however, a problem because it causes the denominator to equal 0 if filled in with the necessary value of x. In my function above, the terms (x + 5) in the numerator and denominator can cancel each other out, leaving a hole in your graph at -5 since x doesn't exist at -5, but the x + 1 doesn't have anything to cancel out with, so this will present as a vertical asymptote in your graph at x = -1, a nonremoveable discontinuity.

6 0
3 years ago
Whats the answer help please
GarryVolchara [31]

Answer:The slope is 6/7

Step-by-step explanation:

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8 0
2 years ago
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What is the answer to this questions it is worth 20 points
irinina [24]
<h2><u>Answer</u> : </h2>

By observing the table we can conclude that for the number of years to travel back double the electricity is required .

i.e. for 5 years = 10 megawatts

therefore, the relationship between x and y can be depicted by the following equation :

\boxed{ \boxed{y = 2x}}

3 0
2 years ago
Jerome's rain gauge showed 13 9/10 centimeters at the end of last month. At the end of this month, the rain gauge showed 15 3/10
nexus9112 [7]
<span>Jerome’s rain gauge shows that there’s 13 9/10 centimeter at the end of last month.
=> for the end of this month, it shows 15 3/10 centimeters.
The question is, how manu centimeter of rain added for this month according to Jerome’s gauge.
=> 15 3/10 cm (this month’s rain measurement)
=> 13 9/10 cm (last month’s rain measurement)
Subtract both numbers.
=> 15 3/10 – 13 9/10
=> convert this first to improper fraction
=> 153/10 – 139/10
=> 14/10
=> 1 4/10 the rain added to for this month

</span>



3 0
3 years ago
Read 2 more answers
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