Question

What is the answer to the question

Answer 1

The equation of the parallel line is y = –2x – 11.

Solution:

Given equation of the line is y = –2x – 5.

Slope of this line is $(m_1)$ = –2

To write the equation parallel to this line and passes through (–4, –3).

If two lines are parallel, then they have the same slope.

$\Rightarrow m_1=m_2$

$\Rightarrow m_2 =-2$

Point-slope formula:

$y-y_1=m(x-x_1)$

Substitute the given values in the formula, we get

$y-(-3)=-2(x-(-4))$

$y+3=-2(x+4)$

$y+3=-2x-8$

Subtract 3 from both sides of the equation.

$y+3-3=-2x-8-3$

$y=-2x-11$

Hence the equation of the parallel line is y = –2x – 11.