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kaheart [24]
3 years ago
14

-4j-1-5j+6= pls help me

Mathematics
2 answers:
alukav5142 [94]3 years ago
7 0

Answer:

-9j+5

combine like terms to get this answer

AlexFokin [52]3 years ago
4 0

Hello

Answer:

-9j+5

Step-by-step explanation:

=-4j-1-5j+6

=-4j-5j+6-1

=-9j+5

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Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = t, y
DochEvi [55]

Answer:

Step-by-step explanation:

At the point (0, 1,0) t = 0

Find the tangent vector:

\frac{dx}{dt}= 1

\frac{dy}{dt}= -4e^{-4t}

\frac{dz}{dt}=5-5t^4

The tangent vector for all points \vec v(t) is

\vec v(t) = \hat {i}-4e^{-4t}\hat{j}+(5-5t^4)\hat{k}

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The vector equation of the tangent line is

(x,y,z) = (0,1,0)+s(\hat{i}-4\hat{j})

The parametric equation for this line are

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4 years ago
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dolphi86 [110]
3x - 2........................................
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Marysya12 [62]

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Step-by-step explanation:

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4 years ago
Seven people sit in a circle.How many ways can this be done if two people A and B sit together ​
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Solving system of equations by substitution
weeeeeb [17]
Y=3x-10 and 3x+2y=16
y=3x-10
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4 years ago
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