The probability that all three people surveyed is an independent probability and the calculated probability is 0.1225
The probability a surveyed driver is worried = 35%
- Number of people surveyed = 3
Since the probability of being worried is independent ;
- Probability = P(A) × P(B) × P(C)
The probability that all 3 surveyed are worried :
- P(worried) × P(worried) × P(worried)
- (0.35 × 0.35 × 0.35) = 0.1225
Therefore, the probability that all three people surveyed are worried is : 0.1225
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2x+y=-10
Multiply both side by 3
2x*3+y*3=-10*3
6x+3y=-30
3x-y=0
Multiply both side by 2
3x*2-y*2=0*2
6x-2y=0
Next, use substitute property
6x+3y=-30
-
6x-2y=0
=
y=-30
3x-y=0
Substitute y with -30
3x-30=0
Add 30 to each side
3x-30+30=0+30
3x=30
Divided both side by 3
3x/3=30/3
x=10, so the solution pair is (10,-30). In this case, there is the first way to solve these two equation.
Then, I would use equation 3x+1.5y=-15 in this question by multiply 2x+y=-10 by multiplying both side by 3/2 to eliminate x and to solve variables for y. Hope it help!
Absolute value makes all things inside positive (make result positive)
so one example is
|x+1|=4
so if you had 3 in it woul dyhave
|3+1|=4
|4|=4
4=4
true
if -5
|-5+1|=4
|-4|=4
4=4
treu
So 7×6=42 and 7×4=28 GCF is 7 so 7x(6x+4)
