4 years ago

Find the equation of the line parallel to y=-x-3 that passes through the point (3, -2)

Mathematics

1 answer:

krek1111 [17]4 years ago

4 0

Answer: y=-x+1 is parallel to y=-x-3

Step-by-step explanation:

line parallel to y=-x-3 that passes through the point (3, -2)

Slope= -1

Point (3,-2)

Y=mx+b

-2=-1(3)+b

-2=-3+b

-2+3=b

1=b

Y= -x+1

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