Find the equation of the line parallel to y=-x-3 that passes through the point (3, -2)
1 answer:
Answer: y=-x+1 is parallel to y=-x-3
Step-by-step explanation:
line parallel to y=-x-3 that passes through the point (3, -2)
Slope= -1
Point (3,-2)
Y=mx+b
-2=-1(3)+b
-2=-3+b
-2+3=b
1=b
Y= -x+1
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Answer:
5π/2 cm
Step-by-step explanation:
Given,
Radius ( r ) = 10 cm
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π * 10 / 4
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Hello,
If the question is to simplify then
4 = 130
2 = 50
1 = 90
3 = 40
:)
