Y^4-4y^3+7y^2-6y-2y^3+8y^2-14y+12=
y^4-6y^3+15y^2-20y+12
or
y^3-4y^2+7y-6=y^3-4y^2+4y+3y-6=
y(y^2-4y+4)+3(y-2)=
y(y-2)^2+3(y-2)=(y-2)[y(y-2)+3]=(y-2)(y^2-2y+3)
(y^3-4y^2+7y-6)(y-2)=(y-2)^2(y^2-2y+3)
35/11 = 3.18.....
This means that out of 35 rounds only 3 of them were free because every 11 rounds 1 is free.
so 35-3=32
You purchased 32 rounds.
Please mark brainliest. This was kind of a confusing question at first.
Answer:
the answer is $27.18 US dollars
Step-by-step explanation: hope you found this helpful
Answer:
x = 14
Step-by-step explanation:
because 4×8 is 32
if x = 14
14 - 10 = 4
14 - 6 = 8
8 x 4 = 32
Answer:
is the sum 78 or 7,878 (i.e. was there a stutter)?
In any event, this sum must be even, so 3 consecutive even integers would be n, n+2 & n+4 whose sum is 3n + 6.
Set that to either 78 or 7878, whichever is intended, & solve for n. If 78 is their grand total, then those 3 consecutive even numbers have to be 24, 26 & 28.
No stress! Just logic! Keep the faith!
Step-by-step explanation:
