Pictures show u have to solve and the answers
Answer: y = -2x - 5
Step-by-step explanation:
The condition for parallelism is that m1 = m2 ie, the gradient of the two lines must be equal.
from the equation given,
y = -2x + 8, m1 = -2, therefore m2 = -2. Since the two line passes through the coordinate of (-1, -3 ) , we substitute for x and y in the equation of a line
y = mx + c to get the value of , the y - intersect.
-3 = -2 x -1 + c
-3 = 2 + c
solve for c
c = -3 - 2
c = -5.
now , to have the equation of the line , we put c = -7 into the equation
y = mx + c
y = -2x - 5
Therefore the equation of the line parallel to the line
y = -2x + 8 is
y = -2x - 7
It’s actually 28t - 10
11(2t-4)+6t-6
22t-4+6t-6 add 22t and 6t
28t-4-6 combine -4 & -6
28t-10
Answer:
The factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....
Step-by-step explanation:
The given expression is:
2q²-5pq-2q+5p
Make a pair of first two terms and last two terms:
(2q²-5pq) - (2q-5p)
Now factor out the common factor from each group.
Note that there is no common factor in second group. So we will take 1 as a common factor.
q(2q-5p) -1(2q-5p)
Now factor the polynomial by factoring out the G.C.F, 2q-5p
(2q-5p) (q-1)
Thus the factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....
