Answer:
Step-by-step explanation:first use parenthisis to seperate it and make it eisier to solve..sorry if my spelling is bad..
For this case we have the following quadratic equation:

The solutions will be given by:

Where:

Substituting the values we have:

We have two roots:

ANswer:

Y = t*e^(-t/2)
y' = t' [e^(-t/2)] + t [e^(-t/2)]' = e^(-t/2) + t[e^(-t/2)][-1/2]=
y' = [e^(-t/2)] [1 - t/2] = (1/2)[e^(-t/2)] [2 - t] = - (1/2) [e^-t/2)] [t -2]
Answer:
12/7
Step-by-step explanation:
Answer:
It’s true
Step-by-step explanation:
If you have two even numbers, both will have 2 as a factor. So 2 would be a factor of the GCF. With 2 a factor of the GCF, no matter what anything else is, the GCF will be even.