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<span>A linear equation in one variable has a single unknown quantity called a variable represented by a letter. Eg: ‘x’, where ‘x’ is always to the power of 1. This means there is no ‘ x² ’ or ‘ x³ ’ in the equation.The process of finding out the variable value that makes the equation true is called ‘solving’ the equation.An equation is a statement that two quantities are equivalent.For example, this linear equation: x<span> + 1 = 4 </span>means that when we add 1 to the unknown value, ‘x’, the answer is equal to 4.To solve linear equations, you add, subtract, multiply and divide both sides of the equation by numbers and variables, so that you end up with a single variable on one side and a single number on the other side. As long as you always do the same thing to BOTH sides of the equation, and do the operations in the correct order, you will get to the solution.</span><span><span>For this example, we only need to subtract 1 from both sides of the equation in order to isolate 'x' and solve the equation:x<span> + 1 </span>-<span> 1 = 4 </span>-<span> 1</span>Now simplifying both sides we have:x<span> + 0 = 3</span>So:</span><span>x<span> = 3</span></span></span><span>With some practice you will easily recognise what operations are required to solve an equation.Here are possible ways of solving a variety of linear equation types.<span>Example 1, Solve for ‘x’ :</span>x<span> + 1 = </span>-31. Subtract 1 from both sides:x<span> + 1 </span>-<span> 1 = </span>-<span>3 </span>-<span> 1</span>2. Simplify both sides:x<span> = </span>-4<span>Example 2, Solve for ‘x’ :</span>-<span>2x = 12</span>1. Divide both sides by -2:2. Simplify both sides:x<span> = </span>-6<span>Example 3, Solve for ‘x’ :</span>1. Multiply both sides by 3:2. Simplify both sides:<span>x = </span>-6<span>Example 4, Solve for ‘x’ :</span><span>2x + 1 = </span>-171. Subtract 1 from both sides:<span>2x + 1 </span>-<span> 1 = </span>-<span>17 </span>-<span> 1</span>2. Simplify both sides:<span>2x = </span>-183. Divide both sides by 2:4. Simplify both sides:<span>x = </span>-9<span>Example 5, Solve for ‘x’ :</span>1. Multiply both sides by 9:2. Simplify both sides:<span>3x = 36</span>3. Divide both sides by 3:4. Simplify both sides:x = 12<span>Example 6, Solve for ‘x’ :</span> 1. Multiply both sides by 3: 2. Simplify both sides:<span> x + 1 = 21</span> 3. Subtract 1 from both sides:<span> x + 1 </span>-<span> 1 = 21 </span>-<span> 1</span> 4. Simplify both sides:x = 20<span>Example 7, Solve for ‘x’ :</span><span>7(x </span>-<span> 1) = 21</span>1. Divide both sides by 7:2. Simplify both sides:<span>x </span>-<span> 1 = 3</span>3. Add 1 to both sides:<span>x </span>-<span> 1 + 1 = 3 + 1</span>4. Simplify both sides:x = 4<span>Example 8, Solve for ‘x’ :</span>1. Multiply both sides by 5:2. Simplify both sides:<span>3(x </span>-<span> 1) = 30</span>3. Divide both sides by 3:4. Simplify both sides:<span>x </span>-<span> 1 = 10</span>5. Add 1 to both sides:<span>x </span>-<span> 1 + 1 = 10 + 1</span>6. Simplify both sides:x<span> = 11</span><span>Example 9, Solve for ‘x’ :</span><span>5x + 2 = 2x + 17</span>1. Subtract 2x from both sides:<span>5x + 2 </span>-<span> 2x = 2x + 17 </span>-<span> 2x</span>2. Simplify both sides:<span>3x + 2 = 17</span>3. Subtract 2 from both sides:<span>3x + 2 </span>-<span> 2 = 17 </span>-<span> 2</span>4. Simplify both sides:<span>3x = 15</span>5. Divide both sides by 3:6. Simplify both sides:x = 5<span>Example 10, Solve for ‘x’ :</span><span>5(x </span>-<span> 4) = 3x + 2</span>1. Expand brackets:<span>5x </span>-<span> 20 = 3x + 2</span>2. Subtract 3x from both sides:<span>5x </span>-<span> 20 </span>-<span> 3x = 3x + 2 </span>-<span> 3x</span>3. Simplify both sides:<span>2x </span>-<span> 20 = 2</span>4. Add 20 to both sides:<span>2x </span>-<span> 20 + 20 = 2 + 20</span>5. Simplify both sides:<span>2x = 22</span>6. Divide both sides by 2:7. Simplify both sides:x <span>= 11</span></span>
sorry i don't know. this answer.
Domains is x values
Thus
Domains : -5 , 3 , , 4
Range is all y values
Range: 4 , -2, 4 , 3
Answer:
A = 139.5 cm^2
Step-by-step explanation:
Ok, let's break it down into pieces. First let's find the area of the main rectangle. We know that the area of a rectangle is as follows:
A = L x W
A = 9 x 12
A = 108 cm^2
Now we need to find the area of the two triangles. There are two ways to approach this. If you can visualize that you can flip the first triangle and slide it against the second, it becomes a rectangle. Then you can simply use the same formula as before with modified numbers.
L = 7 (height of the triangle
W = 4.5 (base of the triangle (half of 9))
A (both triangles) = 7 x 4.5
A (both triangles) = 31.5 cm^2
If you can't quite figure out how to visualize that, you can simply treat them as two independent right triangles. The formula for the area of a right triangle is as follows:
A = (1/2)b x h
b = 4.5
h = 7
A (first triangle) = (1/2)4.5 x 7
A (first triangle) = 15.75 cm^2
The area of the second triangle is identical
A (second triangle) = 15.75 cm^2
The area of the two triangles added together is
A (both triangles) = A (first triangle) + A (second triangle)
A (both triangles) = 31.5 cm^2
As you can see we got the same answer both ways. Now we just have to add the area of the two triangles to the area of the rectangle
A = 108 + 31.5
A = 139.5 cm^2
