2 years ago

Please help due tonight!!

Mathematics

1 answer:

Darya [45]2 years ago

4 0

PLEASE STOP GIVING OUT LINKKKSSSS!!!

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3 years ago

A quadratic equation ax^2+bx+c=0 has -11 and 4 as solutions. Find the values of b and c if the value of a is 1 (hint, use zero f

Alina [70]

Answer:

b = 7, c = -44

Step-by-step explanation:

If the quadratic equation has the solutions -11 and 4, the two factors are:

$(x+11)(x-4)=0$

Since when we use the zero factor property we get

x+11=0 ⇒ x= -11

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Now we develop the multiplications between parenthesis:

$(x+11)(x-4)=0\\x^2-4x+11x-44=0\\x^2+7x-44=0$

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Determine the missing number in the equation 13-2=12-?

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so to find ?, you can do:

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