I am looking on the answers, and there is only one case, when a or b or c or d pass: 3|x-3| + 2 = 14. So I assume, that before two is plus. Then:
3|x-3|+2=14 |minus 2
3|x-3|=12 |divide 3
|x-3|=4
From absolute value definition you've got two ways:
x-3=4 or x-3=-4
x=7 or x=-1
And answer d) passes
1 subtract 1 2m - 1 = 3m
<span>2 subtract 2 2m = 1 + m </span>
<span>3 subtract m m - 1 = 2 </span>
<span>4 add 2 + m = 3 </span>
<span>5 subtract 2m -2 + m = 1 </span>
<span>6 add 1 3 = 1 + m
1.5.
2.4
3.1
42
56
63</span>
Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
36 feet to metres = 10.97
first find the final velocity
vf^2 = vi^2 + 2ad
vf^2 = 0 + 2(9.81)(10.97)
vf^2 = 215.2314
vf = 14.6708
vf = vi + at
at = vf - vi
t = (vf - vi)/a
t = (14.6708)/9.81
t = 1.4955seconds
Its B) Create a table that shows a customer will pay if miles needed to travel are 5,9,12, 25.
