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alisha [4.7K]
3 years ago
6

I need help with this as well ty lol

Mathematics
2 answers:
Pie3 years ago
4 0
so you use the formula a^2 + b^2 = c^2
so C will be JL
13m^2 + 17m^2 = c^2
458 m = c^2

to leave C alone you need to square root it

√458m = √c^2
21.4 = C
Lady bird [3.3K]3 years ago
4 0

Answer:

about 21.4

following Pythagorean theorem

JK and KL are the legs

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Answer: 904.78 cu. ft

Step-by-step explanation:

Volume of sphere = 4/3 pi r^3

Assuming 12 ft. is the diameter of the sphere.

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3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

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This implies that:

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p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

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\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

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5 0
3 years ago
WHATS 9+10
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Answer:

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Step-by-step explanation:

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21

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3 years ago
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