All categories

3 years ago

How many whole sandwiches can be made with 3 pounds of turkey if each sandwich has 5 ounces of turkey on it? 4 6 9 10

2 answers:

6 0

The answer is 9. there are 16 ounces in a pound so if you times that by three it is 48 ounces. 9 sandwiches equals 45 ounces

alekssr [168]3 years ago

4 0

Answer:

9 whole sandwiches can be made

Step-by-step explanation:

As we know 1 pound = 16 ounces

Therefore, 3 pounds = 16 × 3 = 48 ounces

There are 48 ounces (3 pounds) of turkey.

In each sandwich turkey is used = 5 ounces

48 ounces turkey is used = 48 ÷ 5 = 9.6 ≈ 9

9 whole sandwiches can be made with 3 pounds of turkey.

You might be interested in

A coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that

mafiozo [28]

Answer:

(a) The significance level of the test is 0.002.

(b) The power of the test is 0.3487.

Step-by-step explanation:

We are given that a coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that the probability is not 0.5.

The test rejects the null hypothesis if either 0 or 10 heads are observed.

Let p = <u><em>probability of obtaining head.</em></u>

So, Null Hypothesis, $H_0$ : p = 0.5

Alternate Hypothesis, $H_A$ : p $\neq$ 0.5

(a) The significance level of the test which is represented by $\alpha$ is the probability of Type I error.

Type I error states the probability of rejecting the null hypothesis given the fact that the null hypothesis is true.

Here, the probability of rejecting the null hypothesis means we obtain the probability of observing either 0 or 10 heads, that is;

P(Type I error) = $\alpha$

P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true) = $\alpha$

Also, the event of obtaining heads when a coin is thrown 10 times can be considered as a binomial experiment.

So, X ~ Binom(n = 10, p = 0.5)

P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true) = $\alpha$

$\binom{10}{0}\times 0.5^{0} \times (1-0.5)^{10-0} +\binom{10}{10}\times 0.5^{10} \times (1-0.5)^{10-10}$ = $\alpha$

$(1\times 1\times 0.5^{10}) +(1 \times 0.5^{10} \times 0.5^{0})$ = $\alpha$

$\alpha$ = 0.0019

So, the significance level of the test is 0.002.

(b) It is stated that the probability of heads is 0.1, and we have to find the power of the test.

Here the Type II error is used which states the probability of accepting the null hypothesis given the fact that the null hypothesis is false.

Also, the power of the test is represented by (1 - $\beta$ ).

So, here, X ~ Binom(n = 10, p = 0.1)

$1-\beta$ = P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true)

$1-\beta$ = $\binom{10}{0}\times 0.1^{0} \times (1-0.1)^{10-0} +\binom{10}{10}\times 0.1^{10} \times (1-0.1)^{10-10}$

$1-\beta$ = $(1\times 1\times 0.9^{10}) +(1 \times 0.1^{10} \times 0.9^{0})$

$1-\beta$ = 0.3487

Hence, the power of the test is 0.3487.

3 0

3 years ago

A high school debate team of 4 is to be chosen from a class of 35. how many possible ways can the team be formed?

Burka [1]

Imagine there are 4 sits for fill for the debate team
we can fill the first sit in 35 different ways, second sit we only have 34 choices , third sit 33 and last sit 32 ways to possible fill it.
35·34·33·32=1,256,640 possible ways the team could be form

4 0

3 years ago

Which statement comparing these measures is true? A microgram is 1,000 times greater than a milligram.

ololo11 [35]

The statement is false.

The statement below is true.
A milligram is 1000 times greater than a microgram.

3 0

3 years ago

I need help with 3, 4, 5, and 6

Ostrovityanka [42]

3. The answer is 18 because 12➗4= 3 so 6*3=18

3 0

3 years ago

3/8=r+2/3 PLease help im really lazy

stira [4]

Answer:

- 7/24

Step-by-step explanation:

Step 1:

3/8 = r + 2/3

Step 2:

9/24 = r + 16/24

Step 3:

9/24 - 16/24 = r

Answer:

- 7/24 = r

Hope This Helps :)

5 0

2 years ago

Read 2 more answers