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skad [1K]
3 years ago
9

How many decigrams equal 1 dekagram

Mathematics
2 answers:
cricket20 [7]3 years ago
4 0
100 decigrams equal 1 decagram
hoa [83]3 years ago
4 0
100 decigrams equal 1 dekagram, hope this helps. :D
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A rectangular painting measures 15 inches by 18 inches and contains a frame of uniform width around the four edges. The perimete
vfiekz [6]

Answer:

3 inches

Step-by-step explanation:

Lenght = 18 inches

Width =15 inches

Perimeter of the rectangular painting and frame = 90 inches

Let X be the width of the frame

The width of the framed picture = 15 + 2x

The length of the framed picture = 18 + 2x

Perimeter = 2 (L + W)

90 = 2(15 + 2x + 18+ 2x)

90 = 2(33 + 4x)

90 = 66 + 8x

8x = 90 - 66

8x = 24

x = 24/8

x = 3 inches

the width of the frame is 3 inches

5 0
3 years ago
A child weighing 22.5 kg has an IV order for Vancomycin Calculate the q8h per dose dosage if the label states that
vodka [1.7K]

Answer:

q8h dosage = 112.5mg

Step-by-step explanation:

Given

Child Weight = 22.5 kg

Daily Intravenous Dosage = 40mg/kg

Type of Dose = q8h

Required

Calculate the q8h per dose

We start by calculating the total daily dosage in mg

This is calculated by multiplying the child weight by the intravenous dosage

Daily Dosage = 22.5kg * 40mg/kg

Daily Dosage = 900mg

This implies that the body weight requires 900 mg daily

Next is to calculate the q8h dosage

q8h means every 8 hours.

q8h dosage = 900mg/8

q8h dosage = 112.5mg

6 0
4 years ago
What is (16^-1/2 x^3/4)^2 simplified?
Hunter-Best [27]

Answer:x^6-16^2/ -64

Step-by-step explanation:


4 0
3 years ago
To the nearest tenth, find the area of a circle with d = 15km. Use 3.14 for . Remember: you must find the radius before you use
AVprozaik [17]

Answer:

radius r = 7.5 km

diameter d = 15 km

circumference C = 47.1238898 km

area A = 176.714587 km2

Step-by-step explanation:

math

3 0
3 years ago
What is the positive slope of the asymptote of (y+11)^2/100-(x-6)^2/4=1? The positive slope of the asymptote is .
VladimirAG [237]

Answer:

the  positive slope of the asymptote = 5

Step-by-step explanation:

Given that:

\frac{(y+11)^2}{100} -\frac{(x-6)^2}{4} =1

Using the standard form of the equation:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}= 1

where:

(h,k) are the center of the hyperbola.

and the y term is in front of the x term  indicating that the  hyperbola opens up and down.

a = distance that indicates  how far above and below of the center the vertices of the hyperbola are.

For the above standard equation; the equation for the asymptote is:

y = \pm \frac{a}{b} (x-h)+k

where;

\frac{a}{b} is the slope

From above;

(h,k) = 11, 100

a^2 = 100

a = \sqrt{100}

a = 10

b^2 =4

b = \sqrt{4}

b = 2

y = \pm \frac{10}{2} (x-11)+2

y = \pm 5 (x-11)+2

y = 5x-53 , -5x -57

Since we are to find the positive slope of the asymptote: we have  

\frac{a}{b} to be  the slope in the equation  y = \pm \frac{10}{2} (y-11)+2

\frac{a}{b}  = \frac{10}{2}

\frac{a}{b}  = 5

Thus, the  positive slope of the asymptote = 5

8 0
3 years ago
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