How long is a wire reaching from the top of a 12-foot pole to a point 6 feet from the base of the pole?

2 answers:

8 0

Using Pythagoras' theorem it is 6 times the sq rt of 5 which is about 13.416 feet to 3 decimal places

Alex17521 [72]3 years ago

4 0

The pole is 12 foot long.

The wire from the top to the ground, 6feet from the pole, forms a right angle triangle.

By Pythagoras' Theorem:

x² = 12² + 6²

x² = 144 + 36

x² = 180 Take the square root of both sides.

x = √180 Use a calculator

x ≈ 13.42 feet.

Length of wire ≈ 13.42 feet.

You might be interested in

2x+5y=20. , -2x+20y=-90. one solution. infinity many ir no solution. use elimination to find your answer

scoundrel [369]

2x+5y=20
X=10-2.5y

-2(10-2.5y)+20y=-90
-20+5y+20y=-90
25y=-70
Y=2.8

2(2.8)+5y=20

5.6+5y=20
5y=14.4
Y=2.88

CHECK:
2(2.8)+5(2.88)=20

5 0

3 years ago

A student solved the following problem and made an error: Triangles ABC and DEF. Angles A and F are congruent and measure 135 de

dmitriy555 [2]

We have that
triangle ABC coordinates
A (0,2) B(2,4) C(0,0)

triangle DEF coordinates
D (2,0) E ( 4,4) F (4,2)

using a graph tool
see the attached figure

therefore

Line 1 Segment AC equals 2. Segment FE equals 2. Segment AC is congruent to segment FE
so
Segment AC equals 2-------> is correct
Segment FE equals 2-----> is correct
Segment AC is congruent to segment FE------> is correct

Line 2 ∠A ≅ ∠F------> is correct

Line 3 Length of segment AB. A (0, 2) B (2, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, d equals square root of quantity 0 minus 2 all squared plus quantity 2 minus 4 all squared, d equals square root of negative 2 squared plus negative 2 squared, d equals square root of 4 plus 4, d equals square root of 8 segment AB = 2.83

find the distance AB
d=√[(4-2)²+(2-0)²]--------> d=√[4+4]-----> d=√8-----> d=2.83
AB=2.83
so
Line 3 is correct

Line 4 Length of segment DE. D (2, 0) E (4, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared, d equals square root of quantity 2 minus 4 all squared plus quantity 0 minus 4 all squared, d equals square root of negative 2 squared plus negative 4 squared, d equals square root of 4 plus 16, then d equals square root of 20 segment DE = 4.47

find the distance DE
d=√[(4-0)²+(4-2)²]--------> d=√[16+4]-----> d=√20-----> d=4.47
DE=4.47
so
Line 4------> is correct

Line 5 segment AB is congruent with segment DE
AB is not congruent with DE
so
Line 5 is not correct

therefore

the answer is
the student make the first mistake in line 5