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Rzqust [24]
3 years ago
15

Chelsea needs to take a taxi home and lives 7 miles away. The taxi company charges $4 plus $1.50 per mile. How much will she pay

?
Question 3 options:

$29.50


$28.00


$14.50


$10.50
Mathematics
2 answers:
Artist 52 [7]3 years ago
4 0
Your answer is C. Good luck! :)
Andreas93 [3]3 years ago
3 0
Y = 1.50x + 4......x = 7
y = 1.50(7) + 4
y = 10.50 + 4
y = 14.50 <===
You might be interested in
What is the solution to y-12=20
vredina [299]

Hey there!

y-12=20

Add 12 to both sides. (do the inverse of subtraction, which is addition)

y=32

Check answer.

32-12=20 <=== checks out :)

I hope this helps!

~kaikers

4 0
3 years ago
Read 2 more answers
Consider the equation below (in screenshot)
frozen [14]

The <em>approximate</em> solution of the equation shown in the picture is x ≈ 39 / 8 (Right choice: B).

<h3>How to find an approximate solution of a one-variable equation</h3>

The solution of the equation is between x = 4 and x = 5. Now we begin by evaluating each side of the expression (f(x) = x² - 5 · x + 4, g(x) = 2 / (x - 1)) at the average of x = 4 and x = 5.

x = (4 + 5) / 2

x = 4.5

f(4.5) = 4.5² - 5 · 4.5 + 1

f(4.5) = - 5 / 4

g(4.5) = 2 / (4.5 - 1)

g(4.5) = 4 / 7

The solution of the equation is between x = 4.5 and x = 5, then we evaluate at the average:

x = (4.5 + 5) / 2

x = 4.75

f(4.75) = 4.75² - 5 · 4.75 + 1

f(4.75) = - 3 / 16

g(4.75) = 2 / (4.75 - 1)

g(4.75) = 8 / 15

The solution of the equation is between x = 4.75 and x = 5, then we evaluate at the average:

x = (4.75 + 5) / 2

x = 4.875

f(4.875) = 4.875² - 5 · 4.875 + 1

f(4.875) = 25 / 64

g(4.875) = 2 / (4.875 - 1)

g(4.875) = 16 / 31

The <em>approximate</em> solution of the equation shown in the picture is x ≈ 39 / 8 (Right choice: B).

To learn more on successive approximations: brainly.com/question/27191494

#SPJ1

7 0
2 years ago
Find m∠FGL.
Lady bird [3.3K]

Answer:

C) \displaystyle 30°

Step-by-step explanation:

Use the Angle Addition Postulate to figure this out:

\displaystyle m∠FGL + m∠LGH = m∠FGH

165° = (x + 15)° + (9x)°

165° = (15 + 10x)°

- 15° - 15°

_____________

\displaystyle \frac{150°}{10} = \frac{[10x]°}{10} \\ \\

\displaystyle 15° = x[Plug this back into the modeled expression for the m∠FGLto get the angle measure of 30°]; \displaystyle 30° = m∠FGL

I am joyous to assist you anytime.

3 0
3 years ago
Read 2 more answers
Is this right???!!!???
katovenus [111]

Answer:

Yeah rectangle should be the answer

3 0
3 years ago
5. A survey of student pizza preferences showed that 43 students preferred cheese, 56 preferred sausage, 39 preferred pepperoni,
cestrela7 [59]

Answer:

P (Cheese) = 0.199, P (Sausage) = 0.259, P (Pepperoni) = 0.181,

P (Supreme) = 0.130, P (Another Kind) = 0.144

and P (Does not like any kind) = 0.088

Step-by-step explanation:

Given:

Number of students who prefer cheese = 43

Number of students who prefer sausage = 56

Number of students who prefer pepperoni = 39

Number of students who prefer supreme = 28

Number of students who prefer another kind = 31

Number of students who did not like any kind = 19

∴ The total number of students surveyed = 43+56+39+28+31+19=216       The number of students who prefer pizza = 43+56+39+28+31=197

The probability that a students likes pizza is,

P(Student\ likes\ pizza)=\frac{No.\ of\ students\ who\ prefer\ pizza}{Total\ no.\ of\ students\ surveyed}

                                     =\frac{197}{216} \\=0.912

The probability that a students does not likes pizza is,

P(Student\ does\ not\ likes\ pizza)=\frac{No.\ of\ students\ who\ does\ not\ prefer\ pizza}{Total\ no.\ of\ students\ surveyed}

                                                   =\frac{19}{216} \\=0.088

The probability distribution of students who prefer different kinds of pizza is:

  • The probability that a student likes cheese:

       P(A\ Student\ prefers\ cheese)=\frac{No.\ of\ students\ who\ prefer\ cheese}{Total\ no.\ of\ students\ surveyed}

                                                       =\frac{43}{216}\\=0.199

  • The probability that a student likes sausage:

        P(A\ Student\ prefers\ sausage)=\frac{No.\ of\ students\ who\ prefer\ sausage}{Total\ no.\ of\ students\ surveyed}

                                                           =\frac{56}{216}\\=0.259

  • The probability that a student likes pepperoni:

       P(A\ Student\ prefers\ pepperoni)=\frac{No.\ of\ students\ who\ prefer\ pepperoni}{Total\ no.\ of\ students\ surveyed}  

                                                             =\frac{39}{216}\\=0.181

  • The probability that a student likes supreme:

       P(A\ Student\ prefers\ supreme)=\frac{No.\ of\ students\ who\ prefer\ supreme}{Total\ no.\ of\ students\ surveyed}

                                                           =\frac{28}{216}\\=0.130

  • The probability that a student likes another kind:

        P(A\ Student\ prefers\ another\ kind)=\frac{No.\ of\ students\ who\ prefer\ another\ kind}{Total\ no.\ of\ students\ surveyed}

                                                                   =\frac{31}{216}\\=0.144

Thus, the probability distribution table is displayed below:

6 0
3 years ago
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