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2 years ago

If something costs 14.50 and I give 15 pound how much do I get back

Mathematics

1 answer:

romanna [79]2 years ago

7 0

Your change is 0.5 because 15 - 14.50 = 0.5

Hope this helps!! :))

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you download a video game on your computer. you have a 60-minute free trial of the game. it takes 5 1/6 minutes to set up the ga

iren2701 [21]

Answer:

B. $5\frac{1}{6}+(7\frac{1}{3})l \leq 60$

Step-by-step explanation:

Given,

The time for set up the game = $5\frac{1}{6}$ minutes,

Also, the time for each level of game is $7\frac{1}{3}$ minutes,

If there are l levels of games,

Then the time taken in all levels of game = $(7\frac{1}{3})l$

Hence, the total time ( in minutes ) = Set up time + time in all level

= $5\frac{1}{6}+(7\frac{1}{3})l$

We have 60-minute of free trial of the game,

So, the total time taken can not be exceed to 60 minutes,

$\implies 5\frac{1}{6}+(7\frac{1}{3})l \leq 60$

Which is the required inequality.

Option 'B' is correct.

5 0

3 years ago

Read 2 more answers

I need help with this two questions.

mezya [45]

Always get rid of denominators first. Multiply both right and left side by 6
-7 (6) = -c (6)/6 + 12(6)
-42 = -c + 72
c = 72 +42
c = 114

rearrange like terms together
42 = 18 - 4x
4x = 18 -42
4x = -24
divide both sides by 4
x = -6

8 0

3 years ago

What is the positive slope of the asymptote of (y+11)^2/100-(x-6)^2/4=1? The positive slope of the asymptote is .

VladimirAG [237]

Answer:

the positive slope of the asymptote = 5

Step-by-step explanation:

Given that:

$\frac{(y+11)^2}{100} -\frac{(x-6)^2}{4} =1$

Using the standard form of the equation:

$\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}= 1$

where:

(h,k) are the center of the hyperbola.

and the y term is in front of the x term indicating that the hyperbola opens up and down.

a = distance that indicates how far above and below of the center the vertices of the hyperbola are.

For the above standard equation; the equation for the asymptote is:

$y = \pm \frac{a}{b} (x-h)+k$

where;

$\frac{a}{b}$ is the slope

From above;

(h,k) = 11, 100

$a^2$ = 100

a = $\sqrt{100}$

a = 10

$b^2 =4$

b = $\sqrt{4}$

b = 2

$y = \pm \frac{10}{2} (x-11)+2$

$y = \pm 5 (x-11)+2$

y = 5x-53 , -5x -57

Since we are to find the positive slope of the asymptote: we have

$\frac{a}{b}$ to be the slope in the equation $y = \pm \frac{10}{2} (y-11)+2$

$\frac{a}{b}$ = $\frac{10}{2}$

$\frac{a}{b}$ = 5

Thus, the positive slope of the asymptote = 5

8 0

2 years ago

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Viktor [21]

Answer:

Volume equals 75.4

You can use the formula V = πr^2 to solve for the volume of a cylinder

8 0

3 years ago

Mr. Smith's class has collected 72 cans in a food drive. They plan to sort the cans into bags, with an equal number of cans in e

Sliva [168]

Answer:

Step-by-step explanation:

They are dividing the number of cans in to x bags equally.

4 0

2 years ago

Read 2 more answers

If something costs 14.50 and I give 15 pound how much do I get back​

If something costs 14.50 and I give 15 pound how much do I get back