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Vlada [557]
3 years ago
10

The midpoint of is point P at (−6,−2). If point E is at (2,−4), what are the coordinates of point F?

Mathematics
1 answer:
blagie [28]3 years ago
4 0
F                                          p -6,-2                        e   2,-4

2 - -6 is 8, so -6-8 = -14   and -4 - -2 = -2, so -2 - -2 = 0
therefore -14,0 is the point f
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Answer:

<em>The Graph is shown below</em>

Step-by-step explanation:

<u>The Graph of a Function</u>

Given the function:

\displaystyle y=g(x)=-\frac{3}{2}(x-2)^2

It's required to plot the graph of g(x). Let's give x some values:

x={-2,0,2,4,6}

And calculate the values of y:

\displaystyle y=g(-2)=-\frac{3}{2}(-2-2)^2=-\frac{3}{2}(-4)^2==-\frac{3}{2}*16=-24

Point (-2,-24)

\displaystyle y=g(0)=-\frac{3}{2}(0-2)^2=-\frac{3}{2}(-2)^2=-\frac{3}{2}*4=-6

Point (0,-6)

\displaystyle y=g(2)=-\frac{3}{2}(2-2)^2=-\frac{3}{2}(0)^2=0

Point (2,0)

\displaystyle y=g(4)=-\frac{3}{2}(4-2)^2=-\frac{3}{2}(2)^2=-\frac{3}{2}*4=-6

Point (4,-6)

\displaystyle y=g(6)=-\frac{3}{2}(6-2)^2=-\frac{3}{2}(4)^2=-\frac{3}{2}*16=-24

Point (6,-24)

The graph is shown in the image below

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