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kompoz [17]
2 years ago
6

Of a loaf of brown bread costs R6, how much will 4 halves cost?​

Mathematics
2 answers:
Tems11 [23]2 years ago
7 0

Answer: R12

Explanation:

Cost of 1 loaf = R6

Cost of 4 halves = 6/2×4

= 6 × 2

= R12

Please click thanks and mark brainliest if you like

Alex Ar [27]2 years ago
3 0

Answer:

R12

Step-by-step explanation:

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A kite on a 100-foot string is fastened to the ground, making a 25° angle with the ground. To the nearest tenth of a foot, how h
lozanna [386]

Answer:  42.3 ft

<u>Step-by-step explanation:</u>

Draw a picture (see attachment)

Given: angle = 25°, hypotenuse = 100, opposite = ???

\sin\theta=\dfrac{opposite}{hypotenuse}\quad \rightarrow \quad \sin25^o=\dfrac{y}{100}\quad \rightarrow \quad 100\ \sin 25^o=y\\

                                                                            \large\boxed{42.3\ ft}=y

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2 years ago
Given y=2x^2-6x+3. X=-1
konstantin123 [22]
Y=2(-1)^2-6(-1)+3
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5 0
3 years ago
I just need help with this one question
Arte-miy333 [17]

Answer: 1/4 chance of picking red

Step-by-step explanation: There are 120 buttons in all, so the fraction of red marbles is 30/120. 30/120 = 1/4

Hope this helps!

7 0
2 years ago
Read 2 more answers
What additional information could be used to prove ΔABC ≅ ΔMQR using SAS? Select two options. m∠A = 64° and AB = MQ = 31 cm CB =
enyata [817]

Answer:

m∠R = 60° and AB ≅ MQ

m∠Q = 56° and CB ≅ RQ

Step-by-step explanation:

Given data :

Prove ΔABC ≅ ΔMQR using SAS

The  missing information to prove ΔABC ≅ ΔMQR using SAS

  • m∠R = 60° and AB ≅ MQ
  • m∠Q = 56° and CB ≅ RQ
3 0
3 years ago
Read 2 more answers
What is the probability a sample of 90 test takers will provide a sample mean test score within 10 points of the population mean
Elena-2011 [213]

Answer:

0.658 is the probability that a sample 90 test takers will provide a sample mean test score within 10 points of the population mean of 502.

Step-by-step explanation:

The following information is missing:

The standard deviation of population is 100.

We are given the following information in the question:

Population mean, μ = 502

Standard Deviation, σ = 100

Sample size, n  = 90

Standard error =

\dfrac{\sigma}{\sqrt{n}} = \dfrac{100}{\sqrt{90}} =  10.54

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(test score within 10 points)

P(492 \leq x \leq 512) \\\\= P(\displaystyle\frac{492 - 502}{10.54} \leq z \leq \displaystyle\frac{512-502}{10.54}) \\\\= P(-0.9487 \leq z \leq 0.9487)\\= P(z \leq 0.9487) - P(z < -0.9487)\\= 0.829 -0.171 = 0.658 = 65.8\%

P(492 \leq x \leq 512) = 65.8\%

0.658 is the probability that a sample 90 test takers will provide a sample mean test score within 10 points of the population mean of 502.

7 0
2 years ago
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