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julia-pushkina [17]
3 years ago
9

a line represented by y = 3x − 1 and a line perpendicular to it intersect at r(1, 2). what is the equation of the perpendicular

line?
Mathematics
1 answer:
Vlada [557]3 years ago
7 0
Y= -1/3x is the equation of tge perpendicular line
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"If two cards are drawn at random without replacement from a standard deck, find the probability that the second card is a face
PolarNik [594]

Answer:

C. P(F|Q) = \dfrac{11}{51}

Step-by-step explanation:

it is to be noted that the question is only asking for the probability of the 2nd card given that the first card was queen (P(F|Q)), and not asking for the probability of 1st card to be queen and 2nd card to be faced cardP(Q\,\text{and}\,F)

we can represent it in an expression:

P(Q\,\text{and}\,F) = P(Q)P(F|Q)

here P(Q) is the first event: Queen

and P(F|Q) is the second event: Faced card, given that the Queen is taken

--------------------------------

we only need to know what is P(F|Q), and that can be found directly found:

let's start with P(Q), what is the probability that the first card is a Queen? Well, there are 4 queens in a standard deck of 52 cards, so the probability should be:

P(Q) = \dfrac{4}{52}

now we have taken our queen, but we haven't put it back in the deck. so the amount of cards in the deck now are 51.

let's calculate P(F|Q),now that one queen is taken out, what is the probability of the next card to be a faced card? Well, in a standard deck there are 12 faced cards, but in our case one queen is already taken out, so there are 11 faced cards in our deck!

P(F|Q) = \dfrac{11}{51}

and this our answer!

8 0
3 years ago
What is the resistance of a 1.00X10^2 -Ω , a 2.50-kΩ , and a 4.00-k Ω resistor connected in parallel?
Andreas93 [3]

Answer:

Therefore, the total Resistance:  R = 93.9 Ω

Step-by-step explanation:

Given

R₁ = 1 × 10²

R₂ = 2.5 kΩ = 2.5 × 10³ Ω

R₃ = 4  kΩ = 4 × 10³ Ω

Given that the given resisters are connected parallel, so using the formula to calculate the total Resistance R:

\frac{1}{R}\:=\:\frac{1}{R_1}\:+\:\frac{1}{R_2}+\frac{1}{R_3}

susbtituting R₁ = 1 × 10², R₂ = 2.5 × 10³ Ω, and R₃ = 4 × 10³ Ω

\frac{1}{R}=\frac{1}{1\times \:10^2}+\frac{1}{2.5\times \:10^3}+\frac{1}{4\times \:10^3}

Multiply by LCM of R, 100, 2500, and 4000:   20000 R

\frac{1}{R}\cdot \:20000R=\frac{1}{1\cdot \:10^2}\cdot \:20000R+\frac{1}{2.5\cdot \:10^3}\cdot \:20000R+\frac{1}{4\cdot \:10^3}\cdot \:20000R

simplify

20000=213R

Switch sides

213R=20000

Divide both sides by 213

\frac{213R}{213}=\frac{20000}{213}

Simplify

R=\frac{20000}{213}

R = 93.9 Ω

Therefore, the total Resistance:  R = 93.9 Ω

4 0
3 years ago
an ice cream company made 38 batches of ice cream in 7.6 hours. assuming A CONSTANT RATE OF PRODUCTION, AT WHAT RATE IN HOURS PE
fenix001 [56]

Answer:

5 batches per hour

Step-by-step explanation:

6 0
3 years ago
4x = 20
andrey2020 [161]

Answer:

b)

x= 5

Step-by-step explanation:

4x = 20

:4

x=5

3 0
4 years ago
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Mary bought 25/50/50 policy with a $100 deductible on collision and $500 deductible on comprehensive coverage. If the base premi
9966 [12]

Answer: 918

Step-by-step explanation:

add 220+245+215+85 together and you get $765 and you multiply this with the 1.20 to get your solution/answer Plz rate and <3

7 0
3 years ago
Read 2 more answers
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