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2 years ago

WILL GIVE BRAINLIEST FOR BEST ANSWER I NEED THIS NOW! THANK YOU!

Mathematics

1 answer:

Neporo4naja [7]2 years ago

6 0

What we know:
Football field is 100 yards in length
End zones are 10 yards each in length
Perimeter between pylons is 306 2/3 yards

What we need to find:
a. Perimeter and area of one end zone
b. Perimeter and area of without end zones
c. Perimeter and area of playing field with end zones

First we need to find the measurements of the field between pylons using the perimeter of 306 2/3 yards. We already know the length is 100 yards so we need to find width (w).

P=2l + 2w
306 2/3=2 (100) + 2w
306 2/3= 200 + 2w
300 2/3-200=200-200+2w
106 2/3=2w
106 2/3/2=2/2w
53 1/3=w

a. Perimeter=2 (10)+2 (53 1/3)=126 2/3 yards
Area=10×53 1/3=533 1/3 yd²
b. Perimeter=2 (100)+2 (53 1/3)=306 2/3 yards
Area=100×53 1/3=5333 1/3 yd²
c. Perimeter=2 (120) + 2 (53 1/3)=346 2/3 yards
Area=120×53 1/3=6400 yd²

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The square of a number decreased by 3 times the number 28 find all possible values for the number

stealth61 [152]

Question:

The square of a number decreased by 3 times the number is 28 find all possible values for the number

Answer:

The possible values of number are 7 and -4

Solution:

Given that the square of a number decreased by 3 times the number is 28

To find: all possible values of number

Let "a" be the unknown number

From given information,

square of a number decreased by 3 times the number = 28

$a^2 - 3a = 28$

$a^2 - 3a - 28 = 0$

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$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0$

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Using the above formula,

$\text { For } a^{2}-3 a-28=0 \text { we have } a=1, b=-3, c=-28$

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Thus the possible values of number are 7 and -4

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3 years ago

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2 years ago

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2 years ago

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If R is the set of all integers with absolute value less than 10, A is its subset containing all natural numbers less than 10 an

Elza [17]

Answer:

See explanation

Step-by-step explanation:

1. R is the set of all integers with absolute value less than 10, thus

$R=\{a\in \mathbb{Z}\ :\ |a|$

2. A is its subset containing all natural numbers less than 10, thus

$A\subset R\\ \\A=\{b\in \mathbb{N}\ :\ b$

3. B is the set of all integer solutions of inequality 2x+5<9 that are less than 10 by absolute value (and therefore, it is also a subset of R). First, solve the inequality:

$2x+5$

Thus,

$B\subset R\\ \\B=\{c\in \mathbb{Z}\ :\ 2c+5$

See the diagram in attached diagram.

Note that

$A\cup B=R\\ \\A\cap B=\{1\}.$

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3 years ago