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maks197457 [2]
3 years ago
14

A number decreased by fifteen is less than two.

Mathematics
1 answer:
Aliun [14]3 years ago
3 0

Let us assume number of n.

The number is decreased by 15.

Decreasing by 15 means, we need to subtract 15 from that number.

So, it would be come n-15.

Now, it is said that the number would become less than 2.

So, we need to setup an inequality:

n-15 is less than 2.

<h3>n-15 < 2  : required inequality .</h3>

Adding 15 on both sides, we get

n-15+15 < 2+15

n < 17.

<h3>So, we could say the number would be less than 17.</h3>
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yes

Step-by-step explanation:

(there really isn't much else to say, it's quite simple)

5 0
3 years ago
Solve for x <br> Pls help I need this for study guide
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3 years ago
I NEED HELP!! please show all work
PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

4^{5x} = 3^{x-2}

\implies \log 4^{5x} = \log 3^{x-2}

Drop the exponents:

\implies 5x \log 4 = (x-2) \log 3

Expand the right side:

\implies 5x \log 4 = x \log 3 - 2 \log 3

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

\implies 5x \log 4 - x \log 3 = - 2 \log 3

\implies x (5 \log 4 - \log 3) = - 2 \log 3

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}

You can stop there, or continue simplifying the solution by using properties of logarithms:

\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }

\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }

\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}

You can condense the solution further using the change-of-base identity,

\implies \boxed{x = -\log_{\frac{1024}3}9}

5 0
2 years ago
-5x+10&gt;-15 help please
nexus9112 [7]

Answer:

Step-by-step explanation:

-5x + 10 > -15 is your original equation.

You need to isolate the x variable.

Start by subtracting 10.

-5x > -25

x > 5

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3 years ago
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2 she has 2 boxers left
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3 years ago
Read 2 more answers
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