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Nat2105 [25]
3 years ago
5

27-(63-8)and(72-63)-8 is it equivalent or not and why

Mathematics
2 answers:
ZanzabumX [31]3 years ago
5 0
They are not equivalent because 27-(63-8) is equal to -28 and (72-63)-8 is equal to 1.<span />
lord [1]3 years ago
3 0
For the first one is
27-(63-8)
27-55
28

The second one is (72-63)-8
9-8
1


They are not equivalent.
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Step-by-step explanation:

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Step-by-step explanation:

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Solve for x.<br><br> x3=125<br><br> Enter your answer in the box.<br><br> x =
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Answer:

x = 5

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source tiger-algebra.com

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Help with this one because I do not know how to do perpendicular plz put explanation with steps worth 50!
Yuri [45]

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line 2x-3y=12 is 3x+2y=34  

Step-by-step explanation:

Given:  

2x-3y=12  

To Find:  

Equation of line passing through ( 16, -7) and is perpendicular to the line  

2x-3y=12  

Solution:  

2x-3y=12 ...........Given  

\therefore y=\dfrac{2}{3}\times x-4

Comparing with,  

y=mx+c  

Where m =slope  

We get  

Slope = m1 = \dfrac{2}{3}  

We know that for Perpendicular lines have product slopes = -1.

m1\times m2=-1

Substituting m1 we get m2 as

\dfrac{2}{3}\times m2=-1\\\\m2=-\dfrac{3}{2}

Therefore the slope of the required line passing through (16 , -7) will have the slope,

m2=-\dfrac{3}{2}  

Now the equation of line in slope point form given by  

(y-y_{1})=m(x-x_{1})  

Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,  

(y-(-7))=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line  

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line  2x-3y=12 is

3x+2y=34  

3 0
3 years ago
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