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Sedaia [141]
3 years ago
13

Why is the lcm of two numbers never less than the larger number?

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
4 0
This involves a bit of logic in thinking about what LCM actually means.

LCM is the least common multiple. A common multiple is a multiple shared by two or more numbers. And by multiple, we mean some number multiplied by successive integers; this set contains multiples of 5 {5, 10, 15, 20, 25...}. You can see that the least (or lowest) common multiple is the lowest multiple shared by two numbers. Like for 6 and 9, you have {6, 12, 18, 24...} and {9, 18...}, so LCM(6,9) = 18. 

Now, if an LCM must be shared by both numbers, and to get a multiple of the largest number, you have to multiply by an integer greater than or equal to 1, then the LCM of two numbers can never be less than the larger of the twi numbers. Generally, if x and y are positive real numbers, and x is greater than y, LCM(x,y)  \leq x. 
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garri49 [273]

Answer:

Quadratic function, None of the above, and ?

Step-by-step explanation:

So remember what I told you about earlier, lets look at that first one.

So we can see that x is increasing by 1 and y is decreasing by 3...And then it increases by 3! And after that another 9! Well, that seems like it is reversing, as it changes from decreasing to increasing in y coordinates. So knowing that is reverses from decreasing to increasing in y, <u>it must be a quadratic function</u>!

Next we have a increase in 1 and a decrease by 17...then 12...then 7 in y. This isnt decreasing by a constant amount like a linear function. It doesnt seem like a obvious exponential decrease either, and it isnt reversing like a quadratic function does. I am going to use something called logarthms, which you don't even need to think about yet, just to make sure that it is not an exponent.  Althouhg the difference in the exponent was only 0.0018, it is a differnece.<u> So this must be a none of the above</u>, sicne none of the functions apply. (If this is incorrect, and it is exponential, then the test is wrong. While the method I used is something found in mid algebra 2, it is still a method of finding a exponent of a number.)

Now we finish up with a change in x of 1, and a change of y by...-11, -11, -11!

Well, what do you think this is, thinking back on what I have said so far.

It is a constant change of -11y and 1x. Remember, a CONSTANT CHANGE.

What do you think it is :)

If you cannot figure it out, let me know in comments.

<u>Hope this is helps you!</u>

5 0
3 years ago
Need help with this please and thank you
Elis [28]

Answer:

the answer is B

Step-by-step explanation:

Each mark represents 20%, you move right three times. 20x3 = 60

60%

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Umnica [9.8K]
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563/9 (amount of numbers you have including the missing height) = 63
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3 years ago
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