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lora16 [44]
3 years ago
7

A safe has a 4 digit lock code that does not include zero as a digit and no digit is repeated what is the probability that the l

ock code consist of all even digits
to find the total number of outcomes for this event find a permutation of ____ things taken 4 at a time
The total number of outcomes is ___
The total number of favorable outcomes is a permutation of ____ things taken 4 at a time
The probability that the lock code consists of all even digits is _____ out of 3,024
Mathematics
1 answer:
Lostsunrise [7]3 years ago
7 0

Answer:

3

4

5

Step-by-step explanation:

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Solve the simultaneous equations
NeTakaya

Answer:

y = 2, x = -1

Step-by-step explanation:

2y - 5x = 9

2y = 9+5x

y = (9+5x) /2

4y + 3x = 5

4((9+5x) /2) + 3x = 5

13x + 18 = 5

13x = -13

x = -1

y = (9+5x) /2

y = (9+5(-1)) /2

y = 2

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Ruben??

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2 years ago
The parabola with equation $y=ax^2+bx+c$ is graphed below:
Mashutka [201]

Answer:

m-n=2

Step-by-step explanation:

Instead of using the standard form, we can use the vertex form of a quadratic equation:

f(x)=a(x-h)^2+k

Where a is the leading coefficient, and (h, k) is our vertex.

Our vertex point is at (2, -4). So, let’s substitute 2 for h and -4 for k:

f(x)=a(x-2)^2-4

Now, we need to determine a.

We know that it passes through the point (4, 12). So, when x is 4, y must be 12. In other words:

12=a((4)-2)^2-4

Solve for a. Subtract within the parentheses:

12=a(2)^2-4

Add 4 to both sides:

16=a(2)^2

Square:

16=4a

Solve:

a=4

Thererfore, the value of a is 4.

So, our function is:

f(x)=4(x-2)^2-4

Now, let’s find our roots. Set the equation to 0 and solve for x:

0=4(x-2)^2-4

4=4(x-2)^2\\1=(x-2)^2\\x-2=\pm1 \\ x=2\pm1 \\ x=3\text{ or } 1

So, our roots are 1 and 3.

The greater root is 3 and the lesser root is 1.

Therefore, m-n, where m>n, is 3-1 or 2.

Our final answer is 2.

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Im so confused any help or sites would be awesome
denpristay [2]
If A = L x W. . . Then L = A/W
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