Let x be a real number.
If x>=0, then |x|=x.
If x<0, then |x|=-x.
Thus, for x=5 and x=-5, |5|=|-5|=5
(-4)+(-7)=(-11) although not sure if this is shown in "number line"
Answer:

Step-by-step explanation:
Put x = -2, x = -1, ... , x = 2 to the equation of the function y = -4x + 5 and calculate the values of y:
for x = -2
y = -4(-2) + 5 = 8 + 5 = 13
for x = -1
y = -4(-1) + 5 = 4 + 5 = 9
for x = 0
y = -4(0) + 5 = 0 + 5 = 5
for x = 1
y = -4(1) + 5 = -4 + 5 = 1
for x = 2
y = -4(2) + 5 = -8 + 5 = -3
3 - 5m
plug in 350 for m
3 - 5(350)
multiply
3 - 1,750
subtract
-1,747
Answer: Systems of linear equations can only have 0, 1, or an infinite number of solutions. These two lines cannot intersect twice. The correct answer is that the system has one solution.
Step-by-step explanation: