Jose and Tia are selling candles for a fundraiser Tia has earned 15$ to Jose $20 what is her ratio of earnings to his?

Evaluate the following. (iii) sin 30° + tan 40° - cosec 60° / cot 45° + cos 60° - sec 30°

bearhunter [10]

Sin 30 = 1/2

tan 45 = 1

Cosec 60 = 2 / √3 = 2√3 / 3

cot 45 = 1

Cos 60 = 1/2

sec 30 = 2 / √3 = 2√3 / 3

_______________________________

[ 1/2 + 1 - 2√3/3 ] ÷ [ 1 + 1/2 - 2√3/3 ] = 1

The face and denominator of the fraction are exactly the same thus the answer is 1 .

4 0

2 years ago

You may use a calculator to complete this test. if 1 egg and 1/3 cup of oil are needed for each bag of brownie mix, how many bag

iren [92.7K]

Answer: 3 Bags

If you go from using 1 egg to 3 eggs, you are multiplying the amount you use by 3. If you multiply 1/3 by 3, you get 1 cup of oil. Apply that to your 1 bag of brownie mix, and you get a total of 3 brownie mix bags.

1*3=3
1/3*3=1

4 0

2 years ago

Find the indicated limit, if it exists.

kondor19780726 [428]

Answer:

d) The limit does not exist

General Formulas and Concepts:

Calculus

Limits

Right-Side Limit: $\displaystyle \lim_{x \to c^+} f(x)$
Left-Side Limit: $\displaystyle \lim_{x \to c^-} f(x)$

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Limit Property [Addition/Subtraction]: $\displaystyle \lim_{x \to c} [f(x) \pm g(x)] = \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)$

Step-by-step explanation:

*Note:

In order for a limit to exist, the right-side and left-side limits must equal each other.

Step 1: Define

Identify

$\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x,\ x < 5\\8,\ x = 5\\x + 3,\ x > 5\end{array}$

Step 2: Find Right-Side Limit

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^+} 5 - x$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} 5 - x = 5 - 5 = 0$

Step 3: Find Left-Side Limit

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^-} x + 3$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8$