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3 years ago

What property is 5i+24+12i

Mathematics

2 answers:

yulyashka [42]3 years ago

8 0

$5i +24 +12i = 17 i +24$

AleksAgata [21]3 years ago

3 0

Algebraic form:

z = 24+17i

Exponential form:

z = 29.410882 × ei 35°18'40″

Trigonometric form:

z = 29.410882 × (cos 35°18'40″ + i sin 35°18'40″)

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IgorLugansk [536]

Answer:

the time is 1.57 sec and the distance is 49.32mm

Step-by-step explanation:

Given that,

The angle is 180°

Angular velocity is 2rev/sec

The radius is 10mm

we are to find the time and distance traveled at that time

The formula is

θ = at

where t is the time,

a is the angular velocity

θ is angle in radian

so,

θ = 180° × π/180°

θ = π

= 3.14

Hence ,

θ = at

3.14 = 2t

t = 1.57sec

let the distance be xmm

$\frac{1.57 \times 180^0}{360} = \frac{x}{20 \pi} \\\\0.785 = \frac{x}{20 \pi} \\\\x = 49.32mm$

Therefore , the time is 1.57 sec and the distance is 49.32mm

7 0

3 years ago

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Please help ASAP !!!!!

alina1380 [7]

Answer:

(-2,4) and (2,0)

Step-by-step explanation:

The graphical solution to the system of equations is simply the point(s) where the graphs of the function intersect or cross each other.

The graphs of the function can be found in the attachment below;

From the graph, the functions intersect at ;

(-2,4) and (2,0)

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3 years ago

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Question 5 (12 points)

Dima020 [189]

Answer:

see attached for diagram

a) √13

b) √29

c) 4

Step-by-step explanation:

Equation of the circle: $(x + 1)^2 + (y - 3)^2 = 16$

⇒ center = (-1, 3)

⇒ radius = √16 = 4

Distance between 2 points formula:

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

a) let (-1, 3) = $(x_1,y_1)$

let (2, 1) = $(x_2, y_2)$

$\implies \sqrt{(2+1)^2+(1-3)^2} =\sqrt{13}$

b) let (-1, 3) = $(x_1,y_1)$

let (4, 1) = $(x_2, y_2)$

$\implies \sqrt{(4+1)^2+(1-3)^2} =\sqrt{29}$

c) let (-1, 3) = $(x_1,y_1)$

let (3, 3) = $(x_2, y_2)$

$\implies \sqrt{(3+1)^2+(3-3)^2} =4$

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2 years ago

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What is an equation of the line that passes through the point (-6,-8) and is parallel to the line x-2y=6?

vfiekz [6]

Answer:

$y=\frac{1}{2}x-5$

Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)
Parallel lines always have the same slope and different y-intercepts

1) Determine the slope (m)

$x-2y=6$

Rearrange this equation into slope-intercept form (this will help us find the slope)

Subtract x from both sides

$x-2y-x=6-x\\-2y=-x+6$

Divide both sides by -2

$y=\frac{1}{2} x-3$

Now, we can identify clearly that the slope of the given line is $\frac{1}{2}$ since it's in the place of m. Because parallel lines always have the same slopes, the line we're currently solving for would therefore have a slope of $\frac{1}{2}$ as well. Plug this into $y=mx+b$ :