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satela [25.4K]
2 years ago
14

How long is a avarage school bus

Mathematics
2 answers:
Degger [83]2 years ago
7 0

Answer:

25-35 feet

Image result for how long is an average school bus

School buses range anywhere from 20 to 45 feet in length. In general, buses that are 20-25 feet long are considered mini or short. While buses that are 25-35 feet long fall into the mid-size category, and buses over 35 feet are full-sized.

Jlenok [28]2 years ago
5 0

Answer:

School buses range anywhere from 20 to 45 feet in length ok?

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Here is a simple probability model for multiple-choice tests. Suppose that each student has probability p of correctly answering
Alla [95]

Answer:

a) The probability that Jodi scores 78% or lower on a 100-question test is 4%.

b) The probability that Jodi scores 78% or lower on a 250-question test is 0.023%.

Step-by-step explanation:

a) To approximate this distribution we have to calculate the mean and the standard distribution.

The mean is the proportion p=0.85.

The standard deviation can be calculates as:

\sigma=\sqrt{\frac{p(1-p)}{n} }= \sqrt{\frac{0.85*(1-0.85)}{100} }=0.04

To calculate the probability that Jodi scores 78% or less on a 100-question test, we first calculate the z-value:

z=\frac{p-p_0}{\sigma} =\frac{0.78-0.85}{0.04} =-1.75

The probability for this value of z is

P(x

The probability that Jodi scores 78% or lower on a 100-question test is 4%.

b) In this case, the number of questions is 250, so the standard deviation needs to be calculated again:

\sigma=\sqrt{\frac{p(1-p)}{n} }= \sqrt{\frac{0.85*(1-0.85)}{250} }=0.02

To calculate the probability that Jodi scores 78% or less on a 250-question test, we first calculate the z-value:

z=\frac{p-p_0}{\sigma} =\frac{0.78-0.85}{0.02} =-3.5

The probability for this value of z is

P(x

The probability that Jodi scores 78% or lower on a 250-question test is 0.023%.

6 0
2 years ago
The sum of the measures of the external angles of any polygon is
Leona [35]

Answer:

The sum of all the exterior angles in a polygon is equal to 360 degrees.

Hope this helps you. Do mark me as brainliest.

3 0
2 years ago
Im confused..I feel as if what I’m learning in class itself is not as difficult as the problems my teacher gives us to take home
RideAnS [48]
Ok, so remember that the derivitive of the position function is the velocty function and the derivitive of the velocity function is the accceleration function

x(t) is the positon function
so just take the derivitive of 3t/π +cos(t) twice
first derivitive is 3/π-sin(t)
2nd derivitive is -cos(t)
a(t)=-cos(t)

on the interval [π/2,5π/2) where does -cos(t)=1? or where does cos(t)=-1?
at t=π
so now plug that in for t in the position function to find the position at time t=π
x(π)=3(π)/π+cos(π)
x(π)=3-1
x(π)=2
so the position is 2







ok, that graph is the first derivitive of f(x)
the function f(x) is increaseing when the slope is positive
it is concave up when the 2nd derivitive of f(x) is positive

we are given f'(x), the derivitive of f(x)
we want to find where it is increasing AND where it is concave down

it is increasing when the derivitive is positive, so just find where the graph is positive (that's about from -2 to 4)

it is concave down when the second derivitive (aka derivitive of the first derivitive aka slope of the first derivitive) is negative
where is the slope negative?
from about x=0 to x=2
and that's in our range of being increasing
so the interval is (0,2)
4 0
3 years ago
What's the next number? 0 , 1/3 , 1/2 , 3/5 , 2/3​
madam [21]

Answer:

The next number of the series 0, 1/3, 1/2, 3/5, and 2/3 is 5/7

Step-by-step explanation:

The given numbers are;

0, 1/3, 1/2, 3/5, and 2/3

The number sequence is formed adding \dfrac{1}{\left (\dfrac{n^2 + n}{2} \right ) } to each (n - 1)th term to get the nth term number in the sequence, with the first term equal to 0, as follows;

For the 2nd term, the (n - 1)th term is 0, and n = 2, gives;

The

0 +\dfrac{1}{\left (\dfrac{2^2 + 2}{2} \right ) } = 0 + \dfrac{1}{3} = \dfrac{1}{3}

For the 3rd term, the (n - 1)th term is 1/3, and n = 3, gives;

\dfrac{1}{3} +\dfrac{1}{\left (\dfrac{3^2 + 3}{2} \right ) } = \dfrac{1}{3} + \dfrac{1}{6} = \dfrac{1}{2}

For the 4th term, the (n - 1)th term is 1/2, and n = 4, gives;

\dfrac{1}{2} +\dfrac{1}{\left (\dfrac{4^2 + 4}{2} \right ) } = \dfrac{1}{2} + \dfrac{1}{10} = \dfrac{3}{5}

For the 5th term, the (n - 1)th term is 3/5, and n = 5, gives;

\dfrac{3}{5} +\dfrac{1}{\left (\dfrac{5^2 + 5}{2} \right ) } = \dfrac{3}{5} + \dfrac{1}{15} = \dfrac{2}{3}

For the next or 6th term, the (n - 1)th term is 2/3, and n = 6, gives;

\dfrac{2}{3} +\dfrac{1}{\left (\dfrac{6^2 + 6}{2} \right ) } = \dfrac{2}{3} + \dfrac{1}{21} =  \dfrac{15}{21} = \dfrac{5}{7}

The next number of the series 0, 1/3, 1/2, 3/5, and 2/3 = 5/7.

6 0
2 years ago
S = { x ; x is a multiple of 8. 0 < x <30 } Describe this set in another method​
Firdavs [7]

Step-by-step explanation:

<em>Hi</em><em>,</em>

<em>Let's</em><em> </em><em>describe</em><em> </em><em>it</em><em> </em><em>in</em><em> </em><em>listing</em><em> </em><em>method</em><em>;</em>

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3 0
2 years ago
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