Solve for x. 47x=27 x = 849 x = 12 x = 2 x = 4

the rectangular post shown at the right measures 2w-30 by w. the poster has an area of 5400 cm^2. what is The value of w ?

borishaifa [10]

Step-by-step explanation:

w(2w - 30) = 5400

2w²- 30w = 5400

2w² - 30w - 5400 = 0

(w - 60 ) ( w + 45 ) = 0

w= 60 w= - 45

only take the positive value

therefore w = 60

3 0

3 years ago

Riverside Elementary School is holding a school-wide election to choose a school color. 5/8 of the voters were for blue 5/9 of t

padilas [110]

Answer:

There were 180 voters for blue color.

Step-by-step explanation:

Let the total number of voters be 'x'.

Given:

Number of Voters for blue color = $\frac{5}{8}x$

Number of Voters for green color = $\frac{5}{9}(x-\frac58x)=\frac59x(1-\frac58)$

Now we will use LCM to make the denominator common we get;

Number of Voters for green color = $\frac59x(\frac88-\frac58)=\frac59x(\frac{8-5}{9})=\frac59x(\frac38)=\frac{15x}{72}$

Number of Voters for red color = 48

We need to find the number of voters for blue color.

Solution:

Now we can say that;

total number of voters is equal to sum of Number of Voters for blue color, Number of Voters for green color and Number of Voters for red color.

framing in equation form we get;

$x=\frac58x+\frac{15x}{72}+48$

Combining like terms we get;

$x-\frac58x-\frac{15x}{72} = 48$

Now we will make denominators common using LCM we get;

$\frac{72x}{72}-\frac{5x\times9}{8\times9}-\frac{15x\times1}{72\times 1} = 48\\\\\frac{72x}{72}-\frac{45x}{72}-\frac{15x}{72} = 48$

Now denominators are common so we will solve the numerators we get;

$\frac{72x-45x-15x}{72}=48\\\\\frac{12x}{72}=48\\\\\frac{x}{6}=48$

Now multiplying both side by 6 we get;

$\frac{1}{6}x\times6=48\times6\\\\x = 288$

Number of voters for blue color = $\frac{5}{8}x=\frac{5}{8}\times 288= 180$

Hence There were 180 voters for blue color.

4 0

4 years ago

The difference of two numbers is 0.77. If the larger number is increased 5 times, then the difference becomes 77. Find the numbe

Lelu [443]

Let the two numbers are x and y

Let larger number = x

and smaller number = y

it means

x-y = 0.77

Now it says larger number is increased 5 times

So it now becomes 5x

So second equation becomes

5x -y =77

Now we have to solve these two equations

x-y = 0.77 and 5x-y = 77

multiply first equation by -1 and then add both equations

-x+y = -0.77

Now on adding we get

-x+5x +y -y = 77-0.77

4x = 76.23

Divide both sides by 4

x=19.0575

We get the larger number , now subtract 0.77 from this , we will get the smaller number

y=19.0575-0.77=18.2875

y=18.2875

Hence the larger number = 19.0575

Smaller number = 18.2875

8 0

3 years ago

Read 2 more answers

This problem has to do with Fahrenheit and Celsius

Vinvika [58]

F = 1.8C + 32

С = -10 ⇒ F = 1.8·(-10) + 32 = 14 ⇒   (-10, 14)
С = 0 ⇒   F = 1.8·(0) + 32 = 32    ⇒ (0, 32)
С = 10 ⇒ F = 1.8·(10) + 32 = 50 ⇒ (10, 50)
С = 20   ⇒ F = 1.8·(20) + 32 = 68   ⇒ (20, 68)

8 0

3 years ago

What is the derivative of the function below?

11111nata11111 [884]

$g(x)=4x-\dfrac{1}{4x}=4x-(4x)^{-1}\\\\\\\\g'(x)=\left[4x-(4x)^{-1}\right]'=(4x)'-\left[(4x)^{-1}\right]'=4-[-1(4x)^{-2}]\cdot4\\\\=4+\dfrac{1}{(4x)^2}\cdot4=4+\dfrac{4}{4^2x^2}=\boxed{4+\dfrac{1}{4x^2}}\\\\Used:\\\\(f(x)-g(x))'=f'(x)-g'(x)\\\\.[f(g(x))]'=f'(g(x))\cdot g'(x)\\\\(x^n)'=nx^{n-1}$

8 0

3 years ago