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densk [106]
3 years ago
14

Solve for x. 47x=27 x = 849 x = 12 x = 2 x = 4

Mathematics
1 answer:
Alla [95]3 years ago
7 0
You need divide by 47 to get x by it self first
You might be interested in
9/10-1/3-1/5 find the fraction
Zanzabum
Find a common multiple in between the denominators.
10 and 3 and 5 -> the least common multiple is 30.

Change all the denominators to 30 by multiplying the top and bottom by the same number.

9/10=27/30
1/3=10/30
1/5=6/30

Subtract!
27/39-10/30-6/30=11/30

The answer is 11/30

Hope this helps!



3 0
3 years ago
Nancy’s morning routine involves getting dressed, eating breakfast, making her bed, and driving to work. Nancy spends ⅓ of the t
Lina20 [59]
26 minutes to get to work
5 0
3 years ago
Suppose the horses in a large stable have a mean weight of 975lbs, and a standard deviation of 52lbs. What is the probability th
Lubov Fominskaja [6]

Answer:

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 975, \sigma = 52, n = 31, s = \frac{52}{\sqrt{31}} = 9.34

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable?

pvalue of Z when X = 975 + 15 = 990 subtracted by the pvalue of Z when X = 975 - 15 = 960. So

X = 990

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{990 - 975}{9.34}

Z = 1.61

Z = 1.61 has a pvalue of 0.9463

X = 960

Z = \frac{X - \mu}{s}

Z = \frac{960 - 975}{9.34}

Z = -1.61

Z = -1.61 has a pvalue of 0.0537

0.9463 - 0.0537 = 0.8926

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

7 0
3 years ago
the distance around a circle (the circumference) is about 3.14 times the diameter. If a circulares table has a diameter of 3 fee
Katyanochek1 [597]
Well.
The relation between the circumference of a circle and its diameter is described by the following equation: Thecircumference=\pi d
where d is the diameter of the circle.
For a giving diameter (d=3ft), we can substitute in the previous equation 
The circumference of a circule= 3.14*3 (you can use ur calculator to find the exact number i guess it will be about 9.42 ft)

I hope it helps.
8 0
3 years ago
Each of the walls in Harvey’s shed are square and have an area of 84 square feet. What is the approximate height, to the nearest
Mariulka [41]

Answer:

B. 9 feet

Step-by-step explanation:

area = side^2

side^2 = 84

side = sqrt(84)

side = 9.2 ft

Each side of a wall measures 9.2 ft.

5 0
3 years ago
Read 2 more answers
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