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kobusy [5.1K]
3 years ago
9

the height of an equilateral triangle is 4 square root 3. What is the perimeter of the equilateral triangle

Mathematics
2 answers:
klemol [59]3 years ago
5 0

Answer:

The perimeter of the equilateral triangle, P = 24 units

Step-by-step explanation:

All sides of an equilateral triangle are equal. The height of the equilateral triangle is given by :

h=\dfrac{\sqrt{3} }{2}\times a

a is the side of triangle

If the height of an equilateral triangle is, h=4\sqrt{3}

Equation (1) becomes,

a=\dfrac{2h}{\sqrt{3} }

Put h in above formula. So,

a=\dfrac{2\times 4\sqrt{3}}{\sqrt{3} }

a = 8

So, the side of triangle is 8. The sum of all sides is called perimeter of any figure. So,

P=8\times 3

P = 24 units

So, the perimeter of the equilateral triangle is 24 units. Hence, this is the required solution.

OLEGan [10]3 years ago
3 0

- I tried solving this but I don't think there's a perimeter for that.

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3 years ago
Express the function graphed on the axes below as a piecewise function.
adoni [48]

Answer:

  f(x) = {x-3 for x ≤ -1; -3x+14 for x > 5}

Step-by-step explanation:

To write the piecewise function, we can consider the pieces one at a time. For each, we need to define the domain, and the functional relation.

__

<h3>Left Piece</h3>

The domain is the horizontal extent. It is shown as -∞ to -1, with -1 included.

The relation has a slope (rise/run) of +1, and would intersect the y-axis at -3 if it were extended.

The first piece can be written ...

  f(x) = x-3 for x ≤ -1

__

<h3>Right Piece</h3>

The domain is shown as 5 to ∞, with 5<em> not included</em>.

The relation is shown as having a slope (rise/run) of (-3)/(1) = -3. If extended, it would intersect the point (5, -1), so we can write the point-slope equation as ...

  y -(-1) = -3(x -5)

  y = -3x +15 -1 = -3x +14

The second piece can be written ...

  f(x) = -3x +14 for x > 5

__

<h3>Whole function</h3>

Putting these pieces together, we have ...

  \boxed{f(x)=\begin{cases}x-3&\text{for }x\le-1\\-3x+14&\text{for }5 < x\end{cases}}

_____

<em>Additional comment</em>

Sometimes it is convenient to write inequalities in number-line order (using < or ≤ symbols). This gives a visual indication of where the variable stands in relation to the limit(s). Perhaps a more conventional way to write the domain for the second piece is, <em>x > 5</em>.

3 0
2 years ago
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