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3 years ago

Luke can paint 919191 portraits in 777 weeks. How many portraits can Luke paint in 444 weeks?

Mathematics

2 answers:

Mice21 [21]3 years ago

7 0

Answer:

525252

Step-by-step explanation:

Darya [45]3 years ago

4 0

<u>Answer: </u>

Number of portraits which luke can paint in 444 weeks = 525,252

<u>Solution: </u>

Given that luke can paint 919191 portraits in 777 weeks

We have to find out how many portraits can Luke paint in 444 weeks

That is in 777 weeks number of portraits paint by Luke = 919191

So in 1 week number of portraits paint by luke = $\frac{919191}{777}$ = 1183

So in 444 weeks number of portraits like can paint = 1183 $\times$ 444 = 525252.

Hence number of portraits which like can paint in 444 weels = 525,252

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Answer:

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2 years ago

B is the midpoint of AC and E' is the midpoint of BD. If A(-9,-4), C(-1, 6), and E(-4,-3), find the coordinates of D.

Ipatiy [6.2K]

The coordinates for D are (-4, -7)

First we must locate point B as it is vital to finding the midpoint of BD. To do this, we take the average of the endpoints AC since B is its midpoint.

x values = -9 + 1 = -8
Then divide by 2 for the average -8/2 = -4

y values = -4 + 6 = 2
Then divide by 2 for the average 2/2 = 1

Therefore B must be (-4, 1)

Now we know the values of E must be the average of B and D. So we can write equations for each coordinate since we know they are averages.

x - values = (Bx + Dx)/2 = Ex
(-4 + Dx)/2 = -4 ---> multiply both sides by 2
-4 + Dx = -8 ---> add -4 to both sides
Dx = -4

y - values = (By + Dy)/2 = Ey
(1 + Dy)/2 = -3 ---> multiply both sides by 2
1 + Dy = -6 ---> subtract 1 from both side
Dy = -7

So the coordinates for D must be (-4, -7)

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3 years ago

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Invest $6,300 in two different accounts the first account paid 11% the second account paid 6% in interest at the end of the year

MAVERICK [17]

Answer: he invested $5300 at 11% and $1000 at 6%

Step-by-step explanation:

Let x represent the amount which he invested in the first account paying 11% interest.

Let y represent the amount which he invested in the second account paying 6% interest.

He Invest $6,300 in two different accounts the first account paid 11% the second account paid 6% in interest. This means that

x + y = 6300

The formula for determining simple interest is expressed as

I = PRT/100

Considering the first account paying 11% interest,

P = $x

T = 1 year

R = 11℅

I = (x × 11 × 1)/100 = 0.11x

Considering the second account paying 6% interest,

P = $y

T = 1 year

R = 6℅

I = (y × 6 × 1)/100 = 0.06y

At the end of the year, he had earned $643 in interest , it means that

0.11x + 0.06y = 643 - - - - - - - - - -1

Substituting x = 6300 - y into equation 1, it becomes

0.11(6300 - y) + 0.06y = 643

693 - 0.11y + 0.06y = 643

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3 years ago

Homework Jim Thompson! PART 2

BlackZzzverrR [31]

Problem 2

Part (a)

The 3D shape formed when rotating around the y axis forms a pencil tip

The shape formed when rotating around the x axis is a truncated cone turned on its side.

------------

Part (b)

Check out the two diagrams below.

============================================================

Problem 3

Answer: Choice A and Choice C

-----------------------

Explanation:

Think of stacks of coins. Let's say we had 2 stacks of 10 quarters each. The quarters are identical, so they must produce identical volumes. Those sub-volumes then add up to the same volume for each stack. Now imagine one stack is perfectly aligned and the other stack is a bit crooked. Has the volume changed for the crooked stack? No, it hasn't. We're still dealing with the same amount of coins and they yield the same volume.

For more information, check out Cavalieri's Principle.

With all that in mind, this leads us to choice C. If the bases are the same, and so are the heights, then we must be dealing with the same volumes.

On the other hand, if one base is wider (while the heights are still equal) then the wider based block is going to have more volume. This leads us to choice A.

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2 years ago