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3 years ago

3(2x-5)=21 What is x?

Mathematics

2 answers:

Oduvanchick [21]3 years ago

8 0

You would solve a problem like this:

3(2x-5)=21

6x-15=21... I multiplied 2x and -5 by 3

6x-15=21

6x-15+15=21+15... I added 15 to both sides so 6x can be alone

6x=36

6x/6=36/6... I divided by 6 from both sides to leave x alone to get the answer:

x=6.

Alexxx [7]3 years ago

7 0

X=6 is your answer .-.

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Which of the following phrases describes a way colons should not be used?

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Answer:

make sure that sentence that comes before the colon is a complete, sentence

Step-by-step explanation:

One way to test whether you have used a colon correctly is to delete the information after the colon.

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3 years ago

A garden is designed in the shape of a rhombus formed

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Answer:

120ft.

Step-by-step explanation:

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2 years ago

Which expression is equivalent to that

kari74 [83]

Answer:

3. 9x

4. D. -5v + 4

Step-by-step explanation:

3. (-3+12)v

= 9v

4. Combine like terms:

(-2v - 3v) + (8 - 4)

= -5v + 4

6 0

3 years ago

Read 2 more answers

Rewrite exponential expressions

Dahasolnce [82]

Answer:

A = 48

Step-by-step explanation:

In this equation, we can factor out the expression $(\frac{1}{7} )^x$ . If we do so, the expression becomes:

$(\frac{1}{7})^x((\frac{1}{7})^{-2} - 1)$

We can simplify to get:

$(\frac{1}{7} )^x(49 - 1)$

and get:

$48*(\frac{1}{7})^x$

Therefore, A = 48

8 0

2 years ago

Finding a polynomial of a given degree with given zeros

galben [10]

Since f(x) is a polynomial with 3rd degree, then it will have 3 roots (zeroes)

One of them is real and the other two are complex conjugate roots

Since the real root is 4, then

x = 4

Since the complex root is (1 - i), then

The other root will be the conjugate of it (1 + i)

x = (1 - i)

x = (1 + i)

To find f(x) we will multiply the three factors of it

We can get the factors from the zeroes

$x=4$

Subtract 4 from both sides

$\begin{gathered} x-4=4-4 \\ x-4=0 \end{gathered}$

The first factor is (x - 4)

$\begin{gathered} x=1-i \\ x-(1-i)=(1-i)-(1-i) \\ x-1+i=0 \end{gathered}$

The second factor is (x - 1 + i)

The third factor is (x - 1 - i)

$f(x)=(x-4)(x-1+i)(x-1-i)$

We will multiply them to find f(x)

$\begin{gathered} (x-1+i)(x-1-i)= \\ x^2-x-ix-x+1+i+ix-i-(i^2)= \\ x^2-2x+1-(-1)= \\ x^2-2x+1+1= \\ x^2-2x+2 \end{gathered}$

Multiply it by (x - 4)

$\begin{gathered} f(x)=(x-4)(x^2-2x+2) \\ f(x)=x^3-2x^2+2x-4x^2+8x-8 \\ f(x)=x^3-6x^2+10x-8 \end{gathered}$

The answer is

$f(x)=x^3-6x^2+10x-8$

5 0

1 year ago